Upside-down numbers: Difference between revisions

m
Line 157:
else
# build next odds, but switch to evens
odds = vec([hi * 10^(ndigits + 1) + 10 * i + lo for i in odds, (hi, lo) in wrappings])
ndigits += 1
odd_index = 0
Line 168:
else
# build next evens, but switch to odds
evens = vec([hi * 10^(ndigits + 1) + 10 * i + lo for i in evens, (hi, lo) in wrappings])
ndigits += 1
even_index = 0
4,102

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