Undulating numbers: Difference between revisions
m
→{{header|Julia}}
Line 437:
print(n, i % 20 == 0 ? "\n" : " ")
end
lastn = 0▼
for (i, n) in enumerate(UndulatingInteger(ubase, 3))
if i == 600
print("\n\nThe 600th undulating number in base $ubase is $n.")
elseif n >
▲ lastn = 0
print("\n\nNumber of undulating numbers in base $ubase less than 2^53 is ",
i - 1, "\n with the largest such number $lastn.\n\n")
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