Anonymous user
Two bullet roulette: Difference between revisions
JavaScript added
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load, load, spin, fire, spin, fire produces 55.405% deaths.
load, load, spin, fire, fire produces 49.889% deaths.
</pre>
=={{header|JavaScript}}==
<lang javascript>
let Pistol = function(method) {
this.fired = false;
this.cylinder = new Array(6).fill(false);
this.trigger = 0;
this.rshift = function() {
this.trigger = this.trigger == 0 ? 5 : this.trigger-1;
}
this.load = function() {
while (this.cylinder[this.trigger]) this.rshift();
this.cylinder[this.trigger] = true;
this.rshift();
}
// actually we don't need this here: just for completeness
this.unload = function() { this.cylinder.fill(false); }
this.spin = function() { this.trigger = Math.floor(Math.random() * 6); }
this.fire = function() {
if (this.cylinder[this.trigger]) this.fired = true;
this.rshift();
}
this.exec = function() {
if (!method) console.error('No method provided');
else {
method = method.toUpperCase();
for (let x = 0; x < method.length; x++)
switch (method[x]) {
case 'F' : this.fire(); break;
case 'L' : this.load(); break;
case 'S' : this.spin(); break;
case 'U' : this.unload(); break;
default: console.error(`Unknown character in method: ${method[x]}`);
}
return this.fired;
}
}
}
// simulating
const ITERATIONS = 25e4;
let methods = 'lslsfsf lslsff llsfsf llsff'.split(' '),
bodyCount;
console.log(`@ ${ITERATIONS.toLocaleString('en')} iterations:`);
console.log();
for (let x = 0; x < methods.length; x++) {
bodyCount = 0;
for (let y = 1; y <= ITERATIONS; y++)
if (new Pistol(methods[x]).exec()) bodyCount++;
console.log(`${methods[x]}:`);
console.log(`deaths: ${bodyCount.toLocaleString('en')} (${(bodyCount / ITERATIONS * 100).toPrecision(3)} %) `);
console.log();
}
</lang>
{{out}}
Example:
<pre>
@ 250,000 iterations:
lslsfsf:
deaths: 139,030 (55.6 %)
lslsff:
deaths: 145,912 (58.4 %)
llsfsf:
deaths: 138,628 (55.5 %)
llsff:
deaths: 125,268 (50.1 %)
</pre>
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