Triplet of three numbers: Difference between revisions
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Line 1,079:
<syntaxhighlight>
n = 6000
len p[] n +
for i = 2 to sqrt
if p[i] = 0
for j = i * 2 step i to
p[j] = 1
.
.
.
for i = 3 to n - 1
if p[i - 1] = 0 and p[i + 3] = 0 and p[i + 5] = 0
print i & ": " & i - 1 & " " & i + 3 & " " & i + 5
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