Triplet of three numbers: Difference between revisions
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(Triplet of three numbers en FreeBASIC) |
(Triplet of three numbers en Python) |
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5738: 5737, 5741, 5743</pre> |
5738: 5737, 5741, 5743</pre> |
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=={{header|Python}}== |
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{{trans|FreeBASIC}} |
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<lang python> |
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#!/usr/bin/python3 |
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N = 6000 |
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p = [None] * 6000 #inicializamos la lista |
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for i in range(2, round(pow(N,0.5))): |
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if not p[i]: |
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for j in range(i*2, N, i): |
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p[j] = 1 |
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for i in range(3, N): |
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if (p[i-1] or p[i+3] or p[i+5]): |
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continue |
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else: |
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print(i, ': ', i-1, ' ', i+3, ' ', i+5) |
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</lang> |
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<pre> |
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Similar a la entrada de FreeBASIC. |
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</pre> |
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<lang Quackery> [ 1 swap times [ i 1+ * ] ] is ! ( n --> n ) |
<lang Quackery> [ 1 swap times [ i 1+ * ] ] is ! ( n --> n ) |
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