Triplet of three numbers: Difference between revisions
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<syntaxhighlight> |
<syntaxhighlight> |
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n = 6000 |
n = 6000 |
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len p[] n + |
len p[] n + 4 |
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for i = 2 to sqrt |
for i = 2 to sqrt len p[] |
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if p[i] = 0 |
if p[i] = 0 |
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for j = i * 2 step i to |
for j = i * 2 step i to len p[] |
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p[j] = 1 |
p[j] = 1 |
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. |
. |
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. |
. |
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. |
. |
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for i = 3 to n |
for i = 3 to n - 1 |
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if p[i - 1] = 0 and p[i + 3] = 0 and p[i + 5] = 0 |
if p[i - 1] = 0 and p[i + 3] = 0 and p[i + 5] = 0 |
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print i & ": " & i - 1 & " " & i + 3 & " " & i + 5 |
print i & ": " & i - 1 & " " & i + 3 & " " & i + 5 |
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