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Tokenize a string: Difference between revisions
XPath 2.0
(XPath 2.0) |
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Line 2,548:
Returns
<pre>"Hello.How.Are.You.Today"</pre>
=={{header|XPath 2.0}}==
<lang XPath>string-join(tokenize("Hello,How,Are,You,Today", ","), ".")</lang>
{{out}}
Hello.How.Are.You.Today
=={{header|XPL0}}==
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