Talk:Successive prime differences: Difference between revisions

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Revision as of 06:54, 27 April 2019 view source rosettacode>Paddy3118 →‎Task background ← Older edit		Revision as of 13:29, 27 April 2019 view source Nigel Galloway (talk \| contribs) 2,183 edits →‎Task background Newer edit →
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	Enjoy. --[[User:Paddy3118\|Paddy3118]] ([[User talk:Paddy3118\|talk]]) 06:54, 27 April 2019 (UTC)		Enjoy. --[[User:Paddy3118\|Paddy3118]] ([[User talk:Paddy3118\|talk]]) 06:54, 27 April 2019 (UTC)
			:It is very well studied, but you must state it slightly differently. Let P2 be the infinite sequence of successive primes (p2_a,P2_b) such that P2_b-P2_a=2. and P4 be the similar infinite sequence (P4_a,P4_b) such that P4_b-P4_a = 4. The your generalization to P2P4 as 3 successive primes with Pa,Pb,Pc with Pb-Pa=2 and Pc-Pb=4 is a search through P2 and P4 to find P2_b=P4_a. An interesting study would be to compute over a large range the length of P2 and P4 and thus predict the length of P2P4. For a given range should the length of P2P4 be the same as P4P2?--[[User:Nigel Galloway\|Nigel Galloway]] ([[User talk:Nigel Galloway\|talk]]) 13:28, 27 April 2019 (UTC)