Talk:State name puzzle

The rules of harmonising

Why don't you get answers of the form:

 ('Wisconsin', 'Kory New') 
   <-> ('Wisconsin', 'New Kory') 
   <-> ('Wisconsin', 'New York') 
   <-> ('Wisconsin', 'Wen Kory') 
   <-> ('York New', 'Wisconsin')

? --Paddy3118 08:16, 29 August 2011 (UTC)

Off the top because Wisconsin was one of the original states. Or put another way ('Wisconsin', 'New Kory') -> ('Wisconsin', 'New Kory') - the new pair doesn't count as "two other U.S. States" --Dgamey 11:36, 29 August 2011 (UTC)

Sorry, that should have read ('Wisconsin', 'Kory New') -> ('Wisconsin', 'New Kory'). Because in (A, B) -> ( C, D), A,B,C, and D need to be distinct otherwise it's not two other states. --Dgamey 14:19, 29 August 2011 (UTC)

Hi Dgamey, I paired Wisconsin with:

 'Kory New'
 'New Kory'
 'New York'
 'Wen Kory'
 and 'York New'

As they don't seem to be duplicates of each other. If the harmonisation where to equate states of two or more words if the individual words are the same, then I could then see that 'New York' is equivalent to 'York New', and 'Kory New' === 'New Kory', but I am not sure of this from the task definition. --Paddy3118 13:57, 29 August 2011 (UTC)

I think the issue is The challenge was to take the names of two U.S. States, mix them all together, then rearrange the letters to form the names of two other U.S. States. So for example, if you paired 'Wisconsin' with 'Kory New', what are the other two states? --Rdm 14:05, 29 August 2011 (UTC)

Huh I thought "no duplicates" means state names with same letter counts are considered the same. --Ledrug 16:10, 29 August 2011 (UTC)