Talk:Permuted multiples: Difference between revisions

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==Ranges to be checked==
I've added a comment to [https://www.mathblog.dk/project-euler-52-integer-same-digits/ Project Euler solutions C# 52] which is awaiting moderation: "The ranges to be checked can be reduced to 10^n->(10^(n+1))/6 i.e 10000->16666 because 16667*6 contains an extra digit.". So fingers crossed I've got that right.--[[User:Nigel Galloway|Nigel Galloway]] ([[User talk:Nigel Galloway|talk]]) 15:01, 17 August 2021 (UTC)
 
At the above zhilongji notes "since x and 3x have the same digits,x%3 == 0 will always be true, so we can search with the start as 10^i+2,and the step as 3." which is correct--[[User:Nigel Galloway|Nigel Galloway]] ([[User talk:Nigel Galloway|talk]]) 15:24, 17 August 2021 (UTC)
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