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Talk:Partial function application: Difference between revisions
The update is OK with me. Java solution.
(→Explicit curry vs Partial application: Anyone else up for it?) |
(The update is OK with me. Java solution.) |
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:::: Thanks Sonia. Anyone else OK with such an update? (Remember, the idea isn't to exclude Go; it is to more explicitely define partial application). --[[User:Paddy3118|Paddy3118]] 21:08, 13 April 2011 (UTC)
: The update is OK with me.
: I used <tt>(partial #'fs #'f1)</tt> to solve Common Lisp. I also solved Java. Java is a statically typed language, so the solution is like Ocaml or Haskell: I have to curry the <tt>fs()</tt> method. I start with this Java code.
: <lang java>static int[] fs(IntegerFunction f, int[] s) {
int[] r = new int[s.length];
for (int i = 0; i < s.length; i++)
r[i] = f.call(s[i]);
return r;
}
static int[] fsf1(int[] s) {
return fs(f1, s);
}</lang>
: This <tt>fsf1()</tt> explicitly curries <tt>fs()</tt>, mentions <tt>s</tt> and passes the return value from <tt>fs()</tt>. I change the code.
: <lang java>interface SequenceFunction {
int[] call(int[] arg);
}
static SequenceFunction fs(final IntegerFunction f) {
return new SequenceFunction() {
public int[] call(int[] s) {
int[] r = new int[s.length];
for (int i = 0; i < s.length; i++)
r[i] = f.call(s[i]);
return r;
}
};
}
static SequenceFunction fsf1 = fs(f1);</lang>
: This <tt>fs()</tt> explicitly curries ''itself''. So <tt>fsf1</tt> never has to mention <tt>s</tt> nor pass the return value from <tt>fs()</tt>. --[[User:Kernigh|Kernigh]] 20:26, 14 April 2011 (UTC)
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