Talk:Monty Hall problem: Difference between revisions

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==AutoHotkey Implementation==

The AHK implementation doesn't show percentages relative to each other, it shows percentages total - should it? In any case, it should be pretty simple to change. Also, I can't figure out why the output is so off - is it, or is it just because of the way I did it? [[User:BR|BR]] 18:39, 12 April 2010 (UTC)

I dont beleive everyone else, This is my theory:

ok lets say each O is a door

door #'s: 1 2 3

doors: O O O

probability 1/3 1/3 1/3

okay each door has a 1/3 chance; but the two on the left have 66% chance.

So now say we pick one for example, door 3 okay so we say that it has a 33% chance.

So now we open door one and it's a goat. Now some think that door one still has a 6% chance and door 3 has 33%

but thats not true because now we only have '''2''' numbers; therefore it's 50/50 chance

and i was looking at using this with big numbers like 10 doors so: we have ten doors

1 2 3 4 5 6 7 8 9 10

O O O O O O O O O O

each one has a 10% chance

now say we open door 9, at this point, you only have a 1 in 10 chance of getting it right. now next step:

lets say we open all the doors except for door 7 and door 9 so looking at this problem with all the doors you would think it's in door 7, BUT thats not true now we just have two doors:

7 9

O O

okay and now they both have a 50/50 chance.

This is what I believe to be true, if you have anything to persuade me, please i really don't understand how it's a 2/3 chance.