Talk:Monty Hall problem: Difference between revisions

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(Monty Hall problem is FALSE yo)
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I've flagged the entry and hopefully someone will take a look and correct it. --[[User:Paddy3118|Paddy3118]] 16:19, 26 September 2009 (UTC)
I've flagged the entry and hopefully someone will take a look and correct it. --[[User:Paddy3118|Paddy3118]] 16:19, 26 September 2009 (UTC)

==AutoHotkey Implementation==
The AHK implementation doesn't show percentages relative to each other, it shows percentages total - should it? In any case, it should be pretty simple to change. Also, I can't figure out why the output is so off - is it, or is it just because of the way I did it? [[User:BR|BR]] 18:39, 12 April 2010 (UTC)


I dont beleive everyone else, This is my theory:
I dont beleive everyone else, This is my theory:

ok lets say each O is a door
alright, now lets say each O is a door-
door #'s: 1 2 3
door #'s: 1 2 3
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probability: 1/3 1/3 1/3
probability: 1/3 1/3 1/3


okay each door has a 1/3 chance; but the two on the left have 66% chance.
okay each door has a 1/3 chance; but the two on the left have 66% chance.correct,
So now say we pick one for example, door 3 okay so we say that it has a 33% chance.
So now say we pick one for example, door 3; awesome possum, so we say that it has a 33% chance of it being a car.
So now we open door one and it's a goat. Now some think that door one still has a 6% chance and door 3 has 33%
So now we open door 2 and it's a goat. Now some think that door one still has a 66% chance and door 3 has 33% chance,
but thats not true because now we only have '''2''' numbers; therefore it's 50/50 chance
but thats not true because now we only have '''2''' numbers; therefore it's 50/50 chance between the two


and i was looking at using this with big numbers like 10 doors so: we have ten doors
and I was looking at this and they were using larger numbers to try and explain it, this is what I think:


1 2 3 4 5 6 7 8 9 10
door #'s: 1 2 3 4 5 6 7 8 9 10
O O O O O O O O O O
doors: O O O O O O O O O O


each one has a 10% chance
So each door has a 10% chance
now say we open door 9, at this point, you only have a 1 in 10 chance of getting it right. now next step:
now say we predict door 9; at this point, you only have a 1 in 10 chance of getting it right. now next step:


lets say we open all the doors except for door 7 and door 9 so looking at this problem with all the doors you would think it's in door 7, BUT thats not true now we just have two doors:
lets say we open all the doors except for door 7 and door 9. Now you would think it's in door 7, BUT thats not true now we just have two doors and TWO doors only not 10 but Two:


7 9
door #'s: 7 9
O O
Doors: O O


okay and now they both have a 50/50 chance.
okay and now they both have a 50/50 chance. PROBLEM?


This is what I believe to be true, if you have anything to persuade me, please i really don't understand how it's a 2/3 chance.
Well then,This is what I think, my friend tells me I'm crazy but I just don't know.