Talk:Inverted syntax: Difference between revisions
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Mark.
== perl vs. perl6 ==
Currently, the perl entry says:
:In perl, inverted syntax can also be used with the ternary operator:
:<lang perl>$a = $ok ? $b : $c; # Traditional syntax
($ok ? $b : $c) = $a; # Inverted syntax
</lang>
But:
<lang>$ perl -le '$ok= 1; $b= 2; $c= 3; ($a ? $b : $c) = $a; print $a'
$ perl -le '$ok= 1; $b= 2; $c= 3; $a = $ok ? $b : $c; print $a'
2
$ perl -le '(1 ? 2 : 3) = $a; print $a'
Can't modify constant item in list assignment at -e line 1, near "$a;"
Execution of -e aborted due to compilation errors.
$ perl --version
This is perl, v5.10.1 ...</lang>
So, in some versions of perl the two statements are both legal, but not equivalent.
I imagine that the inverted syntax shown here could work in some version of perl6. But I do not yet have any working implementation of perl6 yet, so I do not know if there are additional issues -- Raduko? Pugs? Not yet implemented?. Anyways, I think this one could use some clarity. --[[User:Rdm|Rdm]] 14:21, 6 June 2011 (UTC)
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