Talk:Hash join: Difference between revisions

→‎clarification needed: updated status for the REXX code.
m (→‎clarification needed: added verbage about bypass IF statement. -- ~~~~)
(→‎clarification needed: updated status for the REXX code.)
 
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Is Popeye's entry to be '''not''' listed, either because it has no nemesis, or because it wasn't in the 2nd relation list? -- [[User:Gerard Schildberger|Gerard Schildberger]] ([[User talk:Gerard Schildberger|talk]]) 00:41, 17 December 2013 (UTC)
 
(If: not, I'll enable the '''ifPopeye''' statementshouldn't thatbe bypassesin the checkresulting forrelation because it isn't in the abovesecond conditionrelation. See also [[wp:Join_%28SQL%29#Inner_join]]. -- [[User:Gerard SchildbergerAndiPersti|GerardAndreas SchildbergerPerstinger]] ([[User talk:Gerard SchildbergerAndiPersti|talk]]) 0019:4349, 177 DecemberMarch 20132014 (UTC)
 
(If not, I'll enable the '''if''' statement that bypasses the check for the above condition.) -- [[User:Gerard Schildberger|Gerard Schildberger]] ([[User talk:Gerard Schildberger|talk]]) 00:43, 17 December 2013 (UTC)
 
: The above REXX code ('''if''' statement) was removed. -- [[User:Gerard Schildberger|Gerard Schildberger]] ([[User talk:Gerard Schildberger|talk]]) 20:08, 7 March 2014 (UTC)
 
Can the nemeses (plural) be listed on one line (as the REXX example shows)?   To me, it looks cleaner, more succint, less screen (output) clutter. -- [[User:Gerard Schildberger|Gerard Schildberger]] ([[User talk:Gerard Schildberger|talk]]) 00:41, 17 December 2013 (UTC)
 
== Is identity a hash? ==
 
If the easiest way of implementing this is to use the identity function as the hash function, would that qualify? Why or why not? --[[User:Rdm|Rdm]] ([[User talk:Rdm|talk]]) 04:29, 6 January 2014 (UTC)