Talk:Greatest prime dividing the n-th cubefree number: Difference between revisions

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Revision as of 02:07, 6 March 2024 (view source) Petelomax (talk \| contribs) (logic eludes me)		Revision as of 13:41, 6 March 2024 (view source) Petelomax (talk \| contribs) m (→‎The logic of cubes_before()) Newer edit →
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	== The logic of cubes_before() ==		== The logic of cubes_before() ==
	Fairly obviously there are 31 multiples of 8(2^3) less than ~~250~~, and 9 multiples of 27(3^3), however of course we have to account for 8*27 = 216 being in both. I'm pretty sure it's fairly standard fare, but the logic of accounting for >=3 such clashes is eluding me. --[[User:Petelomax\|Petelomax]] ([[User talk:Petelomax\|talk]]) 02:07, 6 March 2024 (UTC)		Fairly obviously there are 31 multiples of 8(2^3) less than 249, and 9 multiples of 27(3^3), however of course we have to account for 8*27 = 216 being in both. I'm pretty sure it's fairly standard fare, but the logic of accounting for >=3 such clashes is eluding me. --[[User:Petelomax\|Petelomax]] ([[User talk:Petelomax\|talk]]) 02:07, 6 March 2024 (UTC)