Talk:Geometric algebra: Difference between revisions
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:::::::::::::::: The axioms themselves do not specify what kind of product they use - which means that the reader should be able to determine that. Of course, other statements will constrain this, but baring considerable familiarity with the topic, we are left with the sort of trial and error (or hypothesis and test) that leads to talk pages as large as this one. Put differently, a general problem with generality is that there's so many ways to do it, and so many of the underlying assumptions are just that: assumptions. --[[User:Rdm|Rdm]] ([[User talk:Rdm|talk]]) 11:47, 20 October 2015 (UTC)
::::::::::::::::: The axioms don't specify what kind of product they use because they ''define'' it. Any product that satisfy these axioms '''IS''' a geometric product. That's what axioms do.--[[User:Grondilu|Grondilu]] ([[User talk:Grondilu|talk]]) 12:01, 20 October 2015 (UTC)
::::::::::::::::::One difficulty here is that the definition uses the term "dimension". And, while we might reasonably assume that we know what a "[[Dimension_(vector_space)|dimension]]" is, you have also declared that multivectors are not vectors. This means that we should not be using the definition of dimension which applies to vectors. I hope you can see the difficulty... --[[User:Rdm|Rdm]] ([[User talk:Rdm|talk]]) 13:29, 20 October 2015 (UTC)
== "Orthonormal basis" ==
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