Talk:Gamma function: Difference between revisions
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(Complex field?) |
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: Hmm, I never saw this form in mathematical literature. Technically, there is no any multiplication of ''f(x)'' by ''dx''. You cannot commute them, if you meant that. And integral operator is not equal to definite integral. The definite integral using the integral operator would be sort of: <math>{\int f}\mid_a^b</math>. --[[User:Dmitry-kazakov|Dmitry-kazakov]] 20:55, 5 March 2009 (UTC) |
: Hmm, I never saw this form in mathematical literature. Technically, there is no any multiplication of ''f(x)'' by ''dx''. You cannot commute them, if you meant that. And integral operator is not equal to definite integral. The definite integral using the integral operator would be sort of: <math>{\int f}\mid_a^b</math>. --[[User:Dmitry-kazakov|Dmitry-kazakov]] 20:55, 5 March 2009 (UTC) |
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==Complex field== |
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Actually Gamma is defined on complex numbers. Is the task about its real part only? --[[User:Dmitry-kazakov|Dmitry-kazakov]] 22:25, 5 March 2009 (UTC) |
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