Talk:Fibonacci sequence: Difference between revisions

Talk:Fibonacci sequence (view source)

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Revision as of 19:55, 2 February 2017 (view source) Hout (talk \| contribs) (→‎Possibly misleading use of 'iterative' in Haskell subsection ?) ← Older edit		Revision as of 14:50, 10 June 2022 (view source) Enter your username (talk \| contribs) m (→‎Alternative: removed space characters adjoining <math> tags causing formula to be blank) Newer edit →
Line 51: <!-- Sorry for the "changing" of someone's comment, but I couldn't read the original formula, so I though an enlarged version would be beneficial to everyone. --- Gerard Schildberger. --> Fibonacci sequence can also be calculated using this formula. <big><big><big><math> Fib[n] = \frac{(1+\sqrt{5})^n - (1-\sqrt{5})^n}{2^n \sqrt{5}} </math></big></big></big> Size of the floating-point type (float, double, long double etc..) will limit how high n can be calulated.