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Talk:Evolutionary algorithm: Difference between revisions
m
→How to make the algorithm scalable for larger target phrases?
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write("%f\n", (27*L*Math.logn(Math.e, L))/L );
}</lang> which produces a very slowly rising value for <math>nL\ln(L)/L</math>.--[[User:EMBee|eMBee]] 16:40, 11 October 2011 (UTC)
::::on a slight tangent, how would that formula look like if i don't pick 1 char but <math>y</math> chars? there is a chance that some chars are unmatched while others are matched, thus reducing the overall chance of getting an improvement
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