Talk:Cipolla's algorithm: Difference between revisions
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--[[User:G.Brougnard|G.Brougnard]] ([[User talk:G.Brougnard|talk]]) 23:27, 26 March 2016 (UTC)
::: That is not helpful.
::: The problem is that we have declared ω is <math>\sqrt{-6}</math> and the identity you are using here assumes integer values (or perhaps gaussian integers). But we already know that ω is not an integer. So this step is not a valid step.
::: Of course, -6 = 7 for our specific example here, so you could just as easily plug in the square root of seven. But the result here would still be invalid because the square root of seven is still not an integer. --[[User:Rdm|Rdm]] ([[User talk:Rdm|talk]]) 23:45, 26 March 2016 (UTC)
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