Talk:AKS test for primes: Difference between revisions
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==Combinations== |
==Combinations== |
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There is a link between the coefficients of the expansion of <math>(x-1)^p</math> and nCr. --[[User:Paddy3118|Paddy3118]] ([[User talk:Paddy3118|talk]]) 20:56, 6 February 2014 (UTC) |
There is a link between the coefficients of the expansion of <math>(x-1)^p</math> and nCr. --[[User:Paddy3118|Paddy3118]] ([[User talk:Paddy3118|talk]]) 20:56, 6 February 2014 (UTC) |
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==Lower Limit== |
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Again... 1 appears as an "is it prime, isn't it prime" candidate. |
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<math>1</math> is prime if all the coefficients of the polynomial expansion of: <math>(x-1)^p - (x^p - 1)</math> |
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are divisible by <math>p</math>. All the coefficients is the empty set. 1 is divisible by absolutely everything in the empty set. Is there a better wording out there? (That doesn't include the phrases "any number not 1" or "any number > 1") [[User:Tim-brown|Tim-brown]] |
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==Lower Limit== |
==Lower Limit== |