Sum of squares: Difference between revisions
Easylang
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return sum
}</syntaxhighlight>
=={{header|EasyLang}}==
<syntaxhighlight lang="easylang">
nums[] = [ 1 2 3 4 5 ]
for v in nums[]
sum += v * v
.
print sum
</syntaxhighlight>
=={{header|Eiffel}}==
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