Sum of primes in odd positions is prime: Difference between revisions

Added 11l
(Added solution for Action!)
(Added 11l)
Line 8:
 
<br><br>
 
=={{header|11l}}==
{{trans|Nim}}
 
<lang 11l>F is_prime(n)
I n == 2
R 1B
I n < 2 | n % 2 == 0
R 0B
L(i) (3 .. Int(sqrt(n))).step(2)
I n % i == 0
R 0B
R 1B
 
print(‘ i p(i) sum’)
V idx = 0
V s = 0
V p = 1
L p < 1000
p++
I is_prime(p)
idx++
I idx % 2 != 0
s += p
I is_prime(s)
print(f:‘{idx:3} {p:3} {s:5}’)</lang>
 
{{out}}
<pre>
i p(i) sum
1 2 2
3 5 7
11 31 89
27 103 659
35 149 1181
67 331 5021
91 467 9923
95 499 10909
99 523 11941
119 653 17959
143 823 26879
</pre>
 
=={{header|Action!}}==
1,480

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