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→{{header|Haskell}}: use ^ operator, added a couple more ways to do it
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=={{header|Haskell}}==
With a list comprehension:
sum $ map (\x -> 1/(x*x)) [1..1000]▼
sum [1 / x ^ 2 | x <- [1..1000]]
With higher-order functions:
In [http://haskell.org/haskellwiki/Pointfree point-free] style:
(sum . map (1/) . map (^2)) [1..1000]
=={{header|J}}==
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