Sum of a series: Difference between revisions
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<pre>-Psi(1, 1001)+(1/6)*Pi^2</pre> |
<pre>-Psi(1, 1001)+(1/6)*Pi^2</pre> |
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=={{header|Mathematica}}== |
=={{header|Mathematica}}/{{header|Wolfram Language}}== |
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This is the straightforward solution of the task: |
This is the straightforward solution of the task: |
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<lang mathematica>Sum[1/x^2, {x, 1, 1000}]</lang> |
<lang mathematica>Sum[1/x^2, {x, 1, 1000}]</lang> |
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