Sum multiples of 3 and 5: Difference between revisions

From Rosetta Code
Content added Content deleted
(→‎{{header|BASIC}}: from history I see that perhaps a count was intended, not a sum)
(REXX added -- another result :-))
Line 26: Line 26:
{{out}}
{{out}}
<pre>233168</pre>
<pre>233168</pre>

=={{header|REXX}}==
<lang rexx>/* REXX ***************************************************************
* 14.05.2013 Walter Pachl
**********************************************************************/
Say mul35()
exit
mul35:
s=0
Do i=1 To 1000
If i//3=0 | i//5=0 Then
s=s+i
End
Return s</lang>
Output:
<pre>234168</pre>

Revision as of 16:06, 14 May 2013

Sum multiples of 3 and 5 is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

The objective is to find the sum of multiplies of 3 or 5 below n within a function. Test it with n = 1000.

BASIC

Works with: FreeBASIC
This example is incorrect. Please fix the code and remove this message.

Details: (Or if the function is right, then the task description should say 'count of multiples of 3 or 5 no greater than a given number.' or some such...)

<lang basic>Declare function mulsum35(n as integer) as integer Function mulsum35(n as integer) as integer

   Dim s as integer
   For i as integer = 1 to n
       If (i mod 3 = 0) or (i mod 5 = 0) then
           s += 1
       End if
   Next i
   Return s

End Function Print mulsum35(1000) Sleep End</lang>

Output:
 467

Perl 6

<lang perl6>sub sum35($n) { [+] grep * %% (3|5), ^$n; }

say sum35 1000;</lang>

Output:
233168

REXX

<lang rexx>/* REXX ***************************************************************

  • 14.05.2013 Walter Pachl
                                                                                                                                            • /

Say mul35() exit mul35: s=0 Do i=1 To 1000

 If i//3=0 | i//5=0 Then
   s=s+i
 End

Return s</lang> Output:

234168