Revision as of 20:10, 5 January 2023 (view source) Aerobar (talk \| contribs) m (Adding the immediate (and slower) solution) ← Older edit		Revision as of 20:10, 5 January 2023 (view source) Aerobar (talk \| contribs) m (→‎Efficient solution) Newer edit →
Line 3,976: ≫ ===Efficient solution=== This is a straightforward way to calculate the sum for higher values of n, taking into account that the sum of multiples of 3 and 5 is the sum of multiples of 3 ~~and~~plus the sum of multiples of 5, minus the sum of multiples of 15 to remove double counting. ≪ → n ≪ 0 1 3 FOR j

Sum multiples of 3 and 5: Difference between revisions

Sum multiples of 3 and 5 (view source)