Anonymous user
Sum multiples of 3 and 5: Difference between revisions
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a slightly more efficient version
<lang Julia>multsum(n, lim) = (occ = div(lim-1, n); div(n*occ*(occ+1), 2))
multsum(n, m, lim) = multsum(n, lim) + multsum(m, lim) - multsum(lcm(n,m), lim)</lang>
=={{header|Lasso}}==
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