Sum multiples of 3 and 5: Difference between revisions

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(Sum multiples of 3 and 5 en Verilog)
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=={{header|Verilog}}==
<lang Verilog>module main;
integer i, suma;
initial begin
suma = 0;
for(i = 1; i <= 999; i=i+1)
begin
if(i % 3 == 0) suma = suma + i;
else if(i % 5 == 0) suma = suma + i;
end
$display(suma);
$finish ;
end
endmodule</lang>



=={{header|Wortel}}==
=={{header|Wortel}}==