Sum multiples of 3 and 5: Difference between revisions
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(→{{header|Perl 6}}: Add Python. (three ways).) |
(→{{header|Python}}: More clear.) |
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divs = [(n-1) // c for c in consts] |
divs = [(n-1) // c for c in consts] |
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sums = [d*c*(1+d)/2 for d,c in zip(divs, consts)] |
sums = [d*c*(1+d)/2 for d,c in zip(divs, consts)] |
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return |
return sums[0] + sums[1] - sums[2] |
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#test |
#test |
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