Sum multiples of 3 and 5: Difference between revisions
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(→{{header|Uiua}}: Alternative solution.) |
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IndicesFive ← MultOffive ↘1⇡End |
IndicesFive ← MultOffive ↘1⇡End |
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/+ |
/+ ◴⊏⊂ Indicesthree IndicesFive ↘1⇡End # join, select and sum |
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</syntaxhighlight> |
</syntaxhighlight> |
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{{out}} |
{{out}} |
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233168 |
233168 |
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</pre> |
</pre> |
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Alternatively, leaving the 0th element in place means index of n == n, so a simpler solution would be: |
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<syntaxhighlight> |
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End ← 1000 |
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MultOf ← ⊚=0◿ |
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/+◴⊂⊃(MultOf3)(MultOf5)⇡End |
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</syntaxhighlight> |
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=={{header|UNIX Shell}}== |
=={{header|UNIX Shell}}== |
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