Sum multiples of 3 and 5: Difference between revisions
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=={{header|D}}==
<lang d>import std.stdio, std.range, std.algorithm;
long sum35(in long n) {
return n.iota.filter!q{ a % 3 == 0 || a % 5 == 0 }.reduce!q{a + b};
}
void main() {
1000.sum35.writeln;
}</lang>
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=={{header|Perl 6}}==
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