String matching: Difference between revisions
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loc = "abab".indexOf("ab") //returns 0
loc = "abab".indexOf("ab", loc+1) //returns 2</syntaxhighlight>
=={{header|sed}}==
The following programs handle the input lines pairwise: If the first string of a pair contains the second string, the former one is shown. (Which means that non-matching pairs are filtered out.)
1. Determining if the first string starts with the second string:
<syntaxhighlight lang="sed">N;/^\(.*\).*\n\1$/!d;s/\n.*//</syntaxhighlight>
2. Determining if the first string contains the second string at any location:
<syntaxhighlight lang="sed">N;/.*\(.*\).*\n\1$/!d;s/\n.*//</syntaxhighlight>
3. Determining if the first string ends with the second string:
<syntaxhighlight lang="sed">N;/\(.*\)\n\1$/!d;s/\n.*//</syntaxhighlight>
{{out}}
<pre>
$ printf '%s\n' abcd bcd wxyz wxy | sed -f match1.sed
wxyz
$ printf '%s\n' abcd be vwxyz wxy | sed -f match2.sed
vwxyz
$ printf '%s\n' abcd abc wxyz xyz | sed -f match3.sed
wxyz
</pre>
=={{header|Seed7}}==
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