Loop over multiple arrays simultaneously: Difference between revisions
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m the example is redundant, it's the same in as in the opening paragraph; also removed the REPL prompt |
added J (though because J abstracts away arrays and looping, the solution is questionable) |
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'(a b c) |
'(a b c) |
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'(1 2 3))</lang> |
'(1 2 3))</lang> |
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=={{header|J}}== |
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(,.":"0)&:>/ 'abc' ; 'ABC' ; 1 2 3 |
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=={{header|Ruby}}== |
=={{header|Ruby}}== |
Revision as of 14:21, 6 August 2009
![Task](http://static.miraheze.org/rosettacodewiki/thumb/b/ba/Rcode-button-task-crushed.png/64px-Rcode-button-task-crushed.png)
You are encouraged to solve this task according to the task description, using any language you may know.
Loop over multiple arrays (or lists or tuples ...) and print the ith element of each. Use your language's "for each" loop if it has one, otherwise iterate through the collection in order with some other loop.
Example, loop over the arrays (a,b,c)
, (A,B,C)
and (1,2,3)
to produce the output
aA1 bB2 cC3
Common Lisp
<lang lisp>(mapc (lambda (&rest args)
(format t "~{~A~}~%" args)) '(|a| |b| |c|) '(a b c) '(1 2 3))</lang>
J
(,.":"0)&:>/ 'abc' ; 'ABC' ; 1 2 3
Ruby
<lang ruby>['a','b','c'].zip(['A','B','C'], [1,2,3]).each {|i,j,k| puts "#{i}#{j}#{k}"}</lang>
Tcl
<lang tcl>foreach i {a b c} j {A B C} k {1 2 3} {
puts "$i$j$k"
}</lang>