Soundex/OCaml: Difference between revisions

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(a soundex version that can switch the language)
 
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Here is a version with very few changes, which allows choosing different languages ('''en''' for English, '''fr'' for French) of type '''lang''', the definition of this type will be hidden in the interface.
Here is a version with very few changes, which allows choosing different languages ('''en''' for English, '''fr''' for French) of type '''lang''', the definition of this type will be hidden in the interface.


<lang ocaml>type lang = char -> string
<syntaxhighlight lang="ocaml">
type lang = char -> string


let en = function
let en = function
Line 49: Line 50:
match dbl [] (List.rev !cl) with
match dbl [] (List.rev !cl) with
| c::rem -> (String.make 1 c) ^ (soundex_aux lang rem)
| c::rem -> (String.make 1 c) ^ (soundex_aux lang rem)
| [] -> invalid_arg "soundex"</lang>
| [] -> invalid_arg "soundex"
</syntaxhighlight>

We provide an additional function to create new lang parameters from simple data set:

<lang ocaml>type lang_set = (int * char list) list

let make_lang ss =
let ss = List.map (fun (d, li) -> string_of_int d, li) ss in
let ss = List.map (fun (d, li) -> List.map (fun c -> c, d) li) ss in
let ss = List.flatten ss in
(fun c -> try List.assoc c ss with Not_found -> "")</lang>


in the interface as the definition of the type '''lang''' is hidden we can use it easily as a classic parameter:
in the interface as the definition of the type '''lang''' is hidden we can use it easily as a classic parameter:


<lang ocaml>type lang
<syntaxhighlight lang="ocaml">
type lang


val en : lang
val en : lang
Line 71: Line 64:


type lang_set = (int * char list) list
type lang_set = (int * char list) list
val make_lang : lang_set -> lang</lang>
val make_lang : lang_set -> lang
</syntaxhighlight>


The '''lang''' parameter for the '''soundex''' function is optional, if omited the english set is used.
The '''lang''' parameter for the '''soundex''' function is optional, if omited the english set is used.
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Test that the function make_lang provide the same results:
Test that the function make_lang provide the same results:


<lang ocaml>open Soundex
<syntaxhighlight lang="ocaml">
open Soundex


let tests = [
let tests = [
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let status = if code1 = code2 then "OK " else "Arg" in
let status = if code1 = code2 then "OK " else "Arg" in
Printf.printf " \"%s\" \t %s %s %s\n" word code1 code2 status
Printf.printf " \"%s\" \t %s %s %s\n" word code1 code2 status
) tests</lang>
) tests
</syntaxhighlight>


We can run this test file with:
We can run this test file with: <code>ocaml soundex.cmo test.ml</code>
ocaml soundex.cmo test.ml

Latest revision as of 08:56, 21 July 2023

Here is a version with very few changes, which allows choosing different languages (en for English, fr for French) of type lang, the definition of this type will be hidden in the interface.

type lang = char -> string

let en = function
  | 'B' | 'F' | 'P' | 'V' -> "1"
  | 'C' | 'G' | 'J' | 'K' | 'Q' | 'S' | 'X' | 'Z' -> "2"
  | 'D' | 'T' -> "3"
  | 'L' -> "4"
  | 'M' | 'N' -> "5"
  | 'R' -> "6"
  | _ -> ""

let fr = function
  | 'B' | 'P' -> "1"
  | 'C' | 'K' | 'Q' -> "2"
  | 'D' | 'T' -> "3"
  | 'L' -> "4"
  | 'M' | 'N' -> "5"
  | 'R' -> "6"
  | 'G' | 'J' -> "7"
  | 'X' | 'Z' | 'S' -> "8"
  | 'F' | 'V' -> "9"
  | _ -> ""

let rec dbl acc = function
  | [] -> (List.rev acc)
  | c::[] -> List.rev(c::acc)
  | c1::(c2::_ as tl) ->
      if c1 = c2
      then dbl acc tl
      else dbl (c1::acc) tl

let pad s =
  match String.length s with
  | 0 -> s ^ "000"
  | 1 -> s ^ "00"
  | 2 -> s ^ "0"
  | 3 -> s
  | _ -> String.sub s 0 3

let soundex_aux lang rem =
  pad(String.concat "" (dbl [] (List.map lang rem)))

let soundex ?(lang=en) s =
  let s = String.uppercase s in
  let cl = ref [] in
  String.iter (fun c -> cl := c :: !cl) s;
  match dbl [] (List.rev !cl) with
  | c::rem -> (String.make 1 c) ^ (soundex_aux lang rem)
  | [] -> invalid_arg "soundex"

in the interface as the definition of the type lang is hidden we can use it easily as a classic parameter:

type lang

val en : lang
val fr : lang

val soundex : ?lang:lang -> string -> string

type lang_set = (int * char list) list
val make_lang : lang_set -> lang

The lang parameter for the soundex function is optional, if omited the english set is used.

We put the implementation in the file soundex.ml and the interface in soundex.mli, then we compile with:

ocamlc -c soundex.mli
ocamlc -c soundex.ml

Test that the function make_lang provide the same results:

open Soundex

let tests = [
  "Soundex"; "Example"; "Sownteks"; "Ekzampul"; "Euler"; "Gauss"; "Hilbert";
  "Knuth"; "Lloyd"; "Lukasiewicz"; "Ellery"; "Ghosh"; "Heilbronn"; "Kant";
  "Ladd"; "Lissajous"; "Wheaton"; "Ashcraft"; "Burroughs"; "Burrows"; "O'Hara" ]

let fr_set = [
  1, ['B'; 'P'];
  2, ['C'; 'K'; 'Q'];
  3, ['D'; 'T'];
  4, ['L'];
  5, ['M'; 'N'];
  6, ['R'];
  7, ['G'; 'J'];
  8, ['X'; 'Z'; 'S'];
  9, ['F'; 'V'];
]

let my_fr = make_lang fr_set ;;

let () =
  print_endline " Word   \t Fr    Check Status";
  List.iter (fun word ->
    let code1 = soundex ~lang:Soundex.fr word in
    let code2 = soundex ~lang:my_fr word in
    let status = if code1 = code2 then "OK " else "Arg" in
    Printf.printf " \"%s\" \t %s  %s  %s\n" word code1 code2 status
  ) tests

We can run this test file with: ocaml soundex.cmo test.ml