Solving coin problems: Difference between revisions

=={{header|Go}}==

This relatively simple program can only solve problems with 2 types of coins (or other objects) or 3 types of coins (but not other objects) without the need for an equation solver. However, it is able to solve all 28 problems of these types which were originally listed in the Perl entry before it was restricted to the subset of those problems (24) involving coins and bills.

 

import (

printAnswers(p, kinds)

}

 

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=={{header|Julia}}==

Uses the JuMP optimization library as a solver. The examples are from the Go code, and a few regex are from the Perl code.

 

const nums = Dict(

coinproblemsolver(DATA)

 

<pre>

If a person has three times as many quarters as dimes and the total amount of money is $5.95,

=={{header|Perl}}==

Coin-type 'word problems' are analyzed into their constituent algebraic relationships, in a format suitable for processing by MAXIMA, a free computer algebra system. NB: MAXIMA <b>must</b> be locally installed for this task to function.

use warnings;

 

Ben has $45.25 in quarters and dimes. If he has 29 less quarters than dimes, how many of each type of coin does he have?

 

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<pre>problem: person 3 times as many quarter as dime and total amount money $ 5.95 , find number quarter and dime .

though all examples below are for 2 and 3 only. A couple (14 and 17) also sail perilously close to getting a divide by zero.

This task was quite a bit of fun, once I got stuck in.

<span style="color: #000080;font-style:italic;">-- demo\rosetta\Solving_coin_problems.exw</span>

<span style="color: #008080;">with</span> <span style="color: #008080;">javascript_semantics</span>

<span style="color: #004080;">integer</span> <span style="color: #000000;">k</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">find</span><span style="color: #0000FF;">(</span><span style="color: #004600;">false</span><span style="color: #0000FF;">,</span><span style="color: #000000;">vused</span><span style="color: #0000FF;">)</span>

<span style="color: #008080;">if</span> <span style="color: #000000;">k</span> <span style="color: #008080;">then</span> <span style="color: #0000FF;">?{</span><span style="color: #008000;">"unused vocab"</span><span style="color: #0000FF;">,</span><span style="color: #000000;">vocab</span><span style="color: #0000FF;">[</span><span style="color: #000000;">k</span><span style="color: #0000FF;">]}</span> <span style="color: #008080;">end</span> <span style="color: #008080;">if</span>

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You just gotta love this Pidgin English! The problem numbering system used below is mine alone.<br>

{{libheader|Wren-sort}}

{{libheader|Wren-fmt}}

 

var Kind = Struct.create("Kind", ["name", "value", "number"])

kinds[1].number = tn - kinds[0].number

printAnswers.call(p, kinds)

 

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