Solve the no connection puzzle: Difference between revisions

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@@ Line 276: / Line 276: @@
     enum Peg { A, B, C, D, E, F, G, H }
-    immutable Peg[2][$] connections =
+    immutable Peg[2][15] connections =
             [[Peg.A, Peg.C], [Peg.A, Peg.D], [Peg.A, Peg.E],
              [Peg.B, Peg.D], [Peg.B, Peg.E], [Peg.B, Peg.F],
@@ Line 294: / Line 294: @@
         G   H";
-    Peg[$] perm = [EnumMembers!Peg];
+    Peg[EnumMembers!Peg.length] perm = [EnumMembers!Peg];
     do if (connections[].all!(con => abs(perm[con[0]] - perm[con[1]]) > 1))
         return board.tr("ABCDEFGH", "%(%d%)".format(perm)).writeln;