Solve a Rubik's cube: Difference between revisions

 

For the single line example, typical timings are around 240 milliseconds which is much faster than Kotlin due, no doubt, to JVM warm up time.

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* A cube 'state' is an int array with 40 entries, the first 20

fmt.Println("\nAverage number of moves =", float64(aggregateMoves)/float64(lineCount))

fmt.Println("\nAverage time =", elapsedTime/int64(lineCount), "milliseconds")

 

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=={{header|Julia}}==

{{trans|Kotlin}}

*

* A cube 'state' is a vector<int> with 40 entries, the first 20

 

pochmann("rubikdata.txt")

Using the 100-line database:

<pre style="height:45ex">

 

To aid readability I've also inserted spaces between each move in the results and added the total moves needed for each line.

 

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println("\nAverage number of moves = ${aggregateMoves.toDouble() / lineCount}")

println("\nAverage time = ${elapsedTime / lineCount} milliseconds")

 

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=={{header|Nim}}==

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let elapsedTime = cpuTime() - startTime

echo &"\nAverage number of moves = {aggregateMoves / lineCount}"

 

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Uses brute-force (width/highscore-first) Fridrich-steps (ie cross,f2l,oll,pll).<br>

Not the fastest (see THRESHOLD) or shortest results (see thistlethwaite) but the code is pretty easy to follow.<br>

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The "hardest case" from http://www.cube20.org with a high threshold. You can try this manually.

Translation/de-golf(hrumph) of Tomas Sirgedas' winning entry from http://tomas.rokicki.com/cubecontest as held in 2004.<br>

Faster and shorter solutions (in most cases) than cfop, however probably nigh on impossible to debug/enhance...

 

 

 

 

 

 

 

 

 

 

 

 

 

=={{header|Wren}}==

 

Despite this, the script is taking an average of just over a second to calculate the number of moves for each line which is probably not too bad for an interpreted language.

*

* A cube 'state' is an int array with 40 entries, the first 20

var elapsedTime = ((endTime - startTime) * 1000).round

System.print("\nAverage number of moves = %(aggregateMoves/lineCount)")

 

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