Show the (decimal) value of a number of 1s appended with a 3, then squared: Difference between revisions
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Elapsed Time: 8.668 ms.
</pre>
=={{header|EasyLang}}==
<syntaxhighlight>
n = 3
for i to 8
print n & " " & pow n 2
n = number ("1" & n)
.
</syntaxhighlight>
{{out}}
<pre>
3 9
13 169
113 12769
1113 1238769
11113 123498769
111113 12346098769
1111113 1234572098769
11111113 123456832098769
</pre>
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