Show the (decimal) value of a number of 1s appended with a 3, then squared: Difference between revisions

Added Lua
(added RPL)
(Added Lua)
Line 646:
7 11111113 123456832098769
</pre>
=={{header|Lua}}==
<syntaxhighlight lang="lua">
do
local n = 0
for i = 1,8 do
local n3 = ( n * 10 ) + 3
io.write( n3, " ", n3 * n3, "\n" )
n = ( n * 10 ) + 1
end
end</syntaxhighlight>
{{out}}
<pre>
3 9
13 169
113 12769
1113 1238769
11113 123498769
111113 12346098769
1111113 1234572098769
11111113 123456832098769
</pre>
 
=={{header|MAD}}==
<syntaxhighlight lang="mad"> NORMAL MODE IS INTEGER
3,032

edits