Show the (decimal) value of a number of 1s appended with a 3, then squared: Difference between revisions

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:: <big><big>(</big></big>'''n''' &nbsp; '''1''''s &nbsp; appended by the digit &nbsp; '''3'''<big><big>)</big></big> &nbsp; and then square the result, &nbsp; &nbsp; where &nbsp; <big> '''0 &nbsp; <= &nbsp; n &nbsp; < &nbsp; 8''' </big>
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;See also
;* [[oeis:A151997]]
 
 
=={{header|11l}}==
7,805

edits