Seven-sided dice from five-sided dice: Difference between revisions
Seven-sided dice from five-sided dice (view source)
Revision as of 22:56, 13 February 2024
, 4 months ago→{{header|EasyLang}}
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{{task|Probability and statistics}}
;Task:
(Given an equal-probability generator of one of the integers 1 to 5
as <code>dice5</code>), create <code>dice7</code> that generates a pseudo-random integer from
1 to 7 in equal probability using only <code>dice5</code> as a source of random
numbers, and check the distribution for at least one million calls using the function created in [[Verify distribution uniformity/Naive|Simple Random Distribution Checker]].
'''Implementation suggestion:'''
<code>dice7</code> might call <code>dice5</code> twice, re-call if four of the 25
combinations are given, otherwise split the other 21 combinations
into 7 groups of three, and return the group index from the rolls.
<small>(Task adapted from an answer [http://stackoverflow.com/questions/90715/what-are-the-best-programming-puzzles-you-came-across here])</small>
<br><br>
=={{header|
{{trans|Python}}
<syntaxhighlight lang="11l">F dice5()
R random:(1..5)
F dice7() -> Int
V r = dice5() + dice5() * 5 - 6
R I r < 21 {(r % 7) + 1} E dice7()
F distcheck(func, repeats, delta)
V bin = DefaultDict[Int, Int]()
L 1..repeats
bin[func()]++
V target = repeats I/ bin.len
V deltacount = Int(delta / 100.0 * target)
assert(all(bin.values().map(count -> abs(@target - count) < @deltacount)), ‘Bin distribution skewed from #. +/- #.: #.’.format(target, deltacount, sorted(bin.items()).map((key, count) -> (key, @target - count))))
print(bin)
distcheck(dice5, 1000000, 1)
distcheck(dice7, 1000000, 1)</syntaxhighlight>
{{out}}
<pre>
DefaultDict([1 = 199586, 2 = 200094, 3 = 198933, 4 = 200824, 5 = 200563])
DefaultDict([1 = 142478, 2 = 142846, 3 = 143056, 4 = 142894, 5 = 143052, 6 = 143147, 7 = 142527])
</pre>
=={{header|Ada}}==
The specification of a package Random_57:
<syntaxhighlight lang="ada">package Random_57 is
type Mod_7 is mod 7;
Line 24 ⟶ 55:
-- a simple implementation
end Random_57;</
Implementation of Random_57:
<syntaxhighlight lang="ada"> with Ada.Numerics.Discrete_Random;
package body Random_57 is
Line 84 ⟶ 113:
begin
Rand_5.Reset(Gen);
end Random_57;</
A main program, using the Random_57 package:
<syntaxhighlight lang="ada">with Ada.Text_IO, Random_57;
procedure R57 is
Line 132 ⟶ 159:
end if;
end Test;
begin
Line 139 ⟶ 165:
Test( 1_000_000, Rand'Access, 0.02);
Test(10_000_000, Rand'Access, 0.01);
end R57;</
{{out}}
<pre>
Sample Size: 10000
Line 170 ⟶ 194:
=={{header|ALGOL 68}}==
{{trans|C}} - note: This specimen retains the original [[Seven-sided dice from five-sided dice#C|C]] coding style.
{{works with|ALGOL 68|Revision 1 - no extensions to language used}}
{{works with|ALGOL 68G|Any - tested with release [http://sourceforge.net/projects/algol68/files/algol68g/algol68g-1.18.0/algol68g-1.18.0-9h.tiny.el5.centos.fc11.i386.rpm/download 1.18.0-9h.tiny]}}
{{works with|ELLA ALGOL 68|Any (with appropriate job cards) - tested with release [http://sourceforge.net/projects/algol68/files/algol68toc/algol68toc-1.8.8d/algol68toc-1.8-8d.fc9.i386.rpm/download 1.8-8d]}}
C's version using no multiplications, divisions, or mod operators:
<
1 + ENTIER (5*random);
Line 212 ⟶ 232:
distcheck(dice5, 1000000, 5);
distcheck(dice7, 1000000, 7)
)</
{{out}}
<pre>
200598, 199852, 199939, 200602, 199009
Line 220 ⟶ 240:
=={{header|AutoHotkey}}==
<
{ Random, v, 1, 5
Return, v
Line 230 ⟶ 250:
IfLess v, 21, Return, (v // 3) + 1
}
}</
<pre>Distribution check:
Line 244 ⟶ 264:
Bucket 6 contains 1485 elements. Skewed.
Bucket 7 contains 1444 elements.</pre>
=={{header|BBC BASIC}}==
{{works with|BBC BASIC for Windows}}
<syntaxhighlight lang="bbcbasic"> MAXRND = 7
FOR r% = 2 TO 5
check% = FNdistcheck(FNdice7, 10^r%, 0.1)
PRINT "Over "; 10^r% " runs dice7 ";
IF check% THEN
PRINT "failed distribution check with "; check% " bin(s) out of range"
ELSE
PRINT "passed distribution check"
ENDIF
NEXT
END
DEF FNdice7
LOCAL x% : x% = FNdice5 + 5*FNdice5
IF x%>26 THEN = FNdice7 ELSE = (x%+1) MOD 7 + 1
DEF FNdice5 = RND(5)
DEF FNdistcheck(RETURN func%, repet%, delta)
LOCAL i%, m%, r%, s%, bins%()
DIM bins%(MAXRND)
FOR i% = 1 TO repet%
r% = FN(^func%)
bins%(r%) += 1
IF r%>m% m% = r%
NEXT
FOR i% = 1 TO m%
IF bins%(i%)/(repet%/m%) > 1+delta s% += 1
IF bins%(i%)/(repet%/m%) < 1-delta s% += 1
NEXT
= s%</syntaxhighlight>
{{out}}
<pre>
Over 100 runs dice7 failed distribution check with 4 bin(s) out of range
Over 1000 runs dice7 failed distribution check with 2 bin(s) out of range
Over 10000 runs dice7 passed distribution check
Over 100000 runs dice7 passed distribution check
</pre>
=={{header|C}}==
<
{
int r, rand_max = RAND_MAX - (RAND_MAX % 5);
Line 265 ⟶ 326:
printf(check(rand7, 7, 1000000, .05) ? "flat\n" : "not flat\n");
return 0;
}</syntaxhighlight>
{{out}}
<pre>
flat
flat
</pre>
=={{header|C sharp}}==
{{trans|Java}}
<syntaxhighlight lang="csharp">
using System;
public class SevenSidedDice
{
Random random = new Random();
static void Main(string[] args)
{
SevenSidedDice sevenDice = new SevenSidedDice();
Console.WriteLine("Random number from 1 to 7: "+ sevenDice.seven());
Console.Read();
}
int seven()
{
int v=21;
while(v>20)
v=five()+five()*5-6;
return 1+v%7;
}
int five()
{
return 1 + random.Next(5);
}
}</syntaxhighlight>
=={{header|C++}}==
This solution tries to minimize calls to the underlying d5 by reusing information from earlier calls.
<syntaxhighlight lang="cpp">template<typename F> class fivetoseven
{
public:
Line 320 ⟶ 413:
test_distribution(d5, 1000000, 0.001);
test_distribution(d7, 1000000, 0.001);
}</
=={{header|Clojure}}==
Uses the verify function defined in
<
(defn dice7 []
Line 338 ⟶ 431:
(doseq [n [100 1000 10000] [num count okay?] (verify dice7 n)]
(println "Saw" num count "times:"
(if okay? "that's" " not") "acceptable"))</
<pre>Saw 0 10 times: not acceptable
Line 364 ⟶ 457:
=={{header|Common Lisp}}==
{{trans|C}}
<
(1+ (random 5)))
Line 370 ⟶ 463:
(loop for d55 = (+ (* 5 (d5)) (d5) -6)
until (< d55 21)
finally (return (1+ (mod d55 7)))))</
<pre>> (check-distribution 'd7 1000)
Line 386 ⟶ 479:
=={{header|D}}==
{{trans|C++}}
<syntaxhighlight lang
import
/// Generates a random number in [1, 5].
int dice5() /*pure nothrow*/ @safe {
return uniform(1, 6);
}
/// Naive, generates a random number in [1, 7] using dice5.
int
immutable int r = dice5() + dice5() * 5 - 6;
return (r < 21) ? (r % 7) + 1 :
}
Line 404 ⟶ 497:
minimizing calls to dice5.
*/
int
static int rem = 0, max = 1;
Line 427 ⟶ 520:
}
void main() /*@safe*/ {
enum int N =
distCheck(&dice5, N, 1);
distCheck(&
distCheck(&
}</
{{out}}
<pre>1
2
3
4
5
1
2
3
4
5
6
7
1
2
3
4
5
6
7
=={{header|E}}==
{{trans|Common Lisp}}
{{improve|E|Write dice7 in a prettier fashion and use the distribution checker once it's been written.}}
<syntaxhighlight lang="e">def dice5() {
return entropy.nextInt(5) + 1
}
Line 470 ⟶ 560:
while ((d55 := 5 * dice5() + dice5() - 6) >= 21) {}
return d55 %% 7 + 1
}</
<syntaxhighlight lang="e">def bins := ([0] * 7).diverge()
for x in 1..1000 {
bins[dice7() - 1] += 1
}
println(bins.snapshot())</
=={{header|EasyLang}}==
<syntaxhighlight>
func dice5 .
return randint 5
.
func dice25 .
return (dice5 - 1) * 5 + dice5
.
func dice7a .
return dice25 mod1 7
.
func dice7b .
repeat
h = dice25
until h <= 21
.
return h mod1 7
.
numfmt 3 0
n = 1000000
len dist[] 7
#
proc checkdist . .
for i to len dist[]
h = dist[i] / n * 7
if abs (h - 1) > 0.01
bad = 1
.
dist[i] = 0
print h
.
if bad = 1
print "-> not uniform"
else
print "-> uniform"
.
.
#
for i to n
dist[dice7a] += 1
.
checkdist
#
print ""
for i to n
dist[dice7b] += 1
.
checkdist
</syntaxhighlight>
{{out}}
<pre>
1.122
1.118
1.121
1.117
0.840
0.842
0.840
-> not uniform
0.996
1.003
1.001
0.997
1.004
0.998
1.001
-> uniform
</pre>
=={{header|Elixir}}==
<syntaxhighlight lang="elixir">defmodule Dice do
def dice5, do: :rand.uniform( 5 )
def dice7 do
dice7_from_dice5
end
defp dice7_from_dice5 do
d55 = 5*dice5 + dice5 - 6 # 0..24
if d55 < 21, do: rem( d55, 7 ) + 1,
else: dice7_from_dice5
end
end
fun5 = fn -> Dice.dice5 end
IO.inspect VerifyDistribution.naive( fun5, 1000000, 3 )
fun7 = fn -> Dice.dice7 end
IO.inspect VerifyDistribution.naive( fun7, 1000000, 3 )</syntaxhighlight>
{{out}}
<pre>
:ok
:ok
</pre>
=={{header|Erlang}}==
<syntaxhighlight lang="erlang">
-module( dice ).
-export( [dice5/0, dice7/0, task/0] ).
dice5() -> random:uniform( 5 ).
dice7() ->
dice7_small_enough( dice5() * 5 + dice5() - 6 ). % 0 - 24
task() ->
verify_distribution_uniformity:naive( fun dice7/0, 1000000, 1 ).
dice7_small_enough( N ) when N < 21 -> N div 3 + 1;
dice7_small_enough( _N ) -> dice7().
</syntaxhighlight>
{{out}}
<pre>
76> dice:task().
ok
</pre>
=={{header|Factor}}==
<syntaxhighlight lang="factor">USING: kernel random sequences assocs locals sorting prettyprint
math math.functions math.statistics math.vectors math.ranges ;
IN: rosetta-code.dice7
! Output a random integer 1..5.
: dice5 ( -- x )
5 [1,b] random
;
! Output a random integer 1..7 using dice5 as randomness source.
: dice7 ( -- x )
0 [ dup 21 < ] [ drop dice5 5 * dice5 + 6 - ] do until
7 rem 1 +
;
! Roll the die by calling the quotation the given number of times and return
! an array with roll results.
! Sample call: 1000 [ dice7 ] roll
: roll ( times quot: ( -- x ) -- array )
[ call( -- x ) ] curry replicate
;
! Input array contains outcomes of a number of die throws. Each die result is
! an integer in the range 1..X. Calculate and return the number of each
! of the results in the array so that in the first position of the result
! there is the number of ones in the input array, in the second position
! of the result there is the number of twos in the input array, etc.
: count-dice-outcomes ( X array -- array )
histogram
swap [1,b] [ over [ 0 or ] change-at ] each
sort-keys values
;
! Verify distribution uniformity/Naive. Delta is the acceptable deviation
! from the ideal number of items in each bucket, expressed as a fraction of
! the total count. Sides is the number of die sides. Die-func is a word that
! produces a random number on stack in the range [1..sides], times is the
! number of times to call it.
! Sample call: 0.02 7 [ dice7 ] 100000 verify
:: verify ( delta sides die-func: ( -- random ) times -- )
sides
times die-func roll
count-dice-outcomes
dup .
times sides / :> ideal-count
ideal-count v-n vabs
times v/n
delta [ < ] curry all?
[ "Random enough" . ] [ "Not random enough" . ] if
;
! Call verify with 1, 10, 100, ... 1000000 rolls of 7-sided die.
: verify-all ( -- )
{ 1 10 100 1000 10000 100000 1000000 }
[| times | 0.02 7 [ dice7 ] times verify ] each
;</syntaxhighlight>
{{out}}
<pre>USE: rosetta-code.dice7 verify-all
{ 0 0 0 1 0 0 0 }
"Not random enough"
{ 0 2 3 1 1 1 2 }
"Not random enough"
{ 17 12 15 11 13 13 19 }
"Not random enough"
{ 140 130 141 148 143 155 143 }
"Random enough"
{ 1457 1373 1427 1433 1443 1382 1485 }
"Random enough"
{ 14225 14320 14216 14326 14415 14084 14414 }
"Random enough"
{ 142599 141910 142524 143029 143353 142696 143889 }
"Random enough"</pre>
=={{header|Forth}}==
{{works with|GNU Forth}}
<syntaxhighlight lang="forth">require random.fs
: d5 5 random 1+ ;
: discard? 5 = swap 1 > and ;
: d7
begin d5 d5 2dup discard? while 2drop repeat
1- 5 * + 1- 7 mod 1+ ;</syntaxhighlight>
{{out}}
<pre>cr ' d7 1000000 7 1 check-distribution .
lower bound = 141429 upper bound = 144285
1 : 143241 ok
2 : 142397 ok
3 : 143522 ok
4 : 142909 ok
5 : 142001 ok
6 : 142844 ok
7 : 143086 ok
-1</pre>
=={{header|Fortran}}==
{{works with|Fortran|95 and later}}
<
implicit none
Line 516 ⟶ 825:
call distcheck(rand7, samples, 0.001)
end program</
{{out}}
<pre>Distribution Uniform
Line 527 ⟶ 836:
Distribution potentially skewed for bucket 6 Expected: 142857 Actual: 142163
Distribution potentially skewed for bucket 7 Expected: 142857 Actual: 142513</pre>
=={{header|FreeBASIC}}==
{{trans|Liberty BASIC}}
<syntaxhighlight lang="freebasic">
Function dice5() As Integer
Return Int(Rnd * 5) + 1
End Function
Function dice7() As Integer
Dim As Integer temp
Do
temp = dice5() * 5 + dice5() -6
Loop Until temp < 21
Return (temp Mod 7) +1
End Function
Dim Shared As Ulongint n = 1000000
Print "Testing "; n; " times"
If Not(distCheck(n, 0.05)) Then Print "Test failed" Else Print "Test passed"
Sleep
</syntaxhighlight>
{{out}}
<pre>
Igual que la entrada de Liberty BASIC.
</pre>
=={{header|Go}}==
<
import (
Line 583 ⟶ 919:
max, flatEnough = distCheck(dice7, 7, calls, 500)
fmt.Println("Max delta:", max, "Flat enough:", flatEnough)
}</
{{out}}
<pre>
Max delta: 356.1428571428696 Flat enough: true
Line 591 ⟶ 927:
=={{header|Groovy}}==
<syntaxhighlight lang="groovy">random = new Random()
int rand5() {
Line 604 ⟶ 939:
}
(raw % 7) + 1
}</
Test:
<
(1..6). each {
def counts = [0g, 0g, 0g, 0g, 0g, 0g, 0g]
Line 632 ⟶ 966:
=============="""
test(it)
}</
{{out}}
<pre style="height:30ex;overflow:scroll;">TRIAL #1
==============
Line 743 ⟶ 1,076:
=={{header|Haskell}}==
<
import Data.List
Line 751 ⟶ 1,084:
let d7 = 5*d51+d52-6
if d7 > 20 then sevenFrom5Dice
else return $ 1 + d7 `mod` 7</
{{out}}
<
[2,3,1,1,6,2,5,6,5,3]</
Test:
<
(1,(142759,True))
(2,(143078,True))
Line 763 ⟶ 1,096:
(5,(142896,True))
(6,(143028,True))
(7,(143130,True))</
=={{header|Icon}} and {{header|Unicon}}==
{{trans|Ruby}}
Uses <code>verify_uniform</code> from [[Simple_Random_Distribution_Checker#Icon_and_Unicon|here]].
<syntaxhighlight lang="icon">
$include "distribution-checker.icn"
Line 787 ⟶ 1,117:
else write ("skewed")
end
</syntaxhighlight>
{{out}}
<pre>
5 142870
Line 803 ⟶ 1,133:
=={{header|J}}==
The first step is to create 7-sided dice rolls from 5-sided dice rolls (<code>rollD5</code>):
<
roll2xD5=: [: rollD5 2 ,~ */ NB. rolls D5 twice for each desired D7 roll (y rows, 2 cols)
toBase10=: 5 #. <: NB. decrements and converts rows from base 5 to 10
Line 809 ⟶ 1,139:
groupin3s=: [: >. >: % 3: NB. increments, divides by 3 and takes ceiling
getD7=: groupin3s@keepGood@toBase10@roll2xD5</
Here are a couple of variations on the theme that achieve the same result:
<
getD7c=: [: (#~ 7&>:) 3 >.@%~ [: 5&#.&.:<:@rollD5 ] , 2:</
The trouble is that we probably don't have enough D7 rolls yet because we compressed out any double D5 rolls that evaluated to 21 or more. So we need to accumulate some more D7 rolls until we have enough. J has two types of verb definition - tacit (arguments not referenced) and explicit (more conventional function definitions) illustrated below:
Here's an explicit definition that accumulates rolls from <code>getD7</code>:
<
n=. */y NB. product of vector y is total number of D7 rolls required
rolls=. '' NB. initialize empty noun rolls
while. n > #
rolls=. rolls, getD7 >. 0.75 * n NB. calcs 3/4 of required rolls and accumulates getD7 rolls
end.
y $ rolls NB. shape the result according to the vector y
)</
Here's a tacit definition that does the same thing:
<
accumD7Rolls=: ] , getD7@getNumRolls NB. accumulates getD7 rolls
isNotEnough=: */@[ > #@] NB. checks if enough D7 rolls accumulated
rollD7t=: ] $ (accumD7Rolls ^: isNotEnough ^:_)&''</
The <code>verb1 ^: verb2 ^:_</code> construct repeats <code>x verb1 y</code> while <code>x verb2 y</code> is true. It is like saying "Repeat accumD7Rolls while isNotEnough".
Example usage:
<
6 4 5 1 4 2 4 5 2 5
rollD7t 2 5 NB. 2 by 5 array of D7 rolls
Line 854 ⟶ 1,181:
1
($@rollD7x -: $@rollD7t) 2 3 5
1</
=={{header|Java}}==
{{trans|Python}}
<syntaxhighlight lang="java">import java.util.Random;
public class SevenSidedDice
{
private static final Random rnd = new Random();
public static void main(String[] args)
{
SevenSidedDice now=new SevenSidedDice();
System.out.println("Random number from 1 to 7: "+now.seven());
}
int seven()
{
int v=21;
while(v>20)
v=five()+five()*5-6;
return 1+v%7;
}
int five()
{
return 1+rnd.nextInt(5);
}
}</syntaxhighlight>
=={{header|JavaScript}}==
{{trans|Ruby}}
<
{
return 1 + Math.floor(5 * Math.random());
Line 875 ⟶ 1,226:
distcheck(dice5, 1000000);
print();
distcheck(dice7, 1000000);</
{{out}}
<pre>1 199792
2 200425
Line 891 ⟶ 1,242:
7 142619 </pre>
=={{header|
{{works with|jq}}
'''Also works with gojq, the Go implementation of jq.'''
In this entry, the results for both a low-entropy and a
high-entropy 5-sided die are shown. The former uses the computer's
clock as a not-very-good PRNG, and the latter uses /dev/random in accordance
with the following invocation:
<syntaxhighlight lang=sh>
#!/bin/bash
< /dev/random tr -cd '0-9' | fold -w 1 | jq -Mcnr -f dice.jq
</syntaxhighlight>
The results employ a two-tailed χ2-test at the 95% confidence level
according to which we are entitled to reject the null hypothesis of
uniform randomness if the χ2 statistic is less than 1.69 or greater
than 16.013, assuming the number of trials is large enough.
See https://www.itl.nist.gov/div898/handbook/eda/section3/eda3674.htm
'''dice.jq'''
<syntaxhighlight lang=jq>
# Output: a PRN in range(0;$n) where $n is .
def prn:
if . == 1 then 0
else . as $n
| (($n-1)|tostring|length) as $w
| [limit($w; inputs)] | join("") | tonumber
| if . < $n then . else ($n | prn) end
end;
# Emit a stream of [value, frequency] pairs
def histogram(stream):
reduce stream as $s ({};
($s|type) as $t
| (if $t == "string" then $s else ($s|tojson) end) as $y
| .[$t][$y][0] = $s
| .[$t][$y][1] += 1 )
| .[][] ;
# sum of squares
def ss(s): reduce s as $x (0; . + ($x * $x));
def chiSquared($expected):
debug # show the actual frequencies
| ss( .[] - $expected ) / $expected;
# The high-entropy 5-sided die
def dice5: 1 + (5|prn);
# The low-entropy 5-sided die
def pseudo_dice5:
def r: (now * 100000 | floor) % 10;
null | until(. and (. < 5); r) | 1 + . ;
# The formal argument dice5 should behave like a 5-sided dice:
def dice7(dice5):
1 + ([limit(7; repeat(dice5))]|add % 7) ;
# Issue a report on the results of a sequence of $n trials using the specified dice
def report(dice; $n):
1.69 as $lower
| 16.013 as $upper
| [histogram( limit($n; repeat(dice)) ) | last]
| chiSquared($n/7) as $x2
| "The χ2 statistic for a trial of \($n) virtual tosses is \($x2).",
"Using a two-sided χ2-test with seven degrees of freedom (\($lower), \($upper)), it is reasonable to conclude that",
(if $x2 < $lower then "this is lower than would be expected for a fair die."
elif $x2 > $upper then "this is higher than would be expected for a fair die."
else "this is consistent with the die being fair."
end) ;
def report($n):
"Low-entropy die results:",
report(dice7(pseudo_dice5); $n),
"",
"High-entropy die results:",
report(dice7(dice5); $n) ;
report(70)
</syntaxhighlight>
{{output}}
<pre>
Low-entropy die results:
["DEBUG:",[19,14,6,18,7,5,1]]
The χ2 statistic for a trial of 70 virtual tosses is 29.2.
Using a two-sided χ2-test with seven degrees of freedom (1.69, 16.013), it is reasonable to conclude that
this is higher than would be expected for a fair die.
High-entropy die results:
["DEBUG:",[9,11,9,10,15,11,5]]
The χ2 statistic for a trial of 70 virtual tosses is 5.4.
Using a two-sided χ2-test with seven degrees of freedom (1.69, 16.013), it is reasonable to conclude that
this is consistent with the die being fair.
</pre>
'''Results for 1,000,000 trials:'''
<pre>
Low-entropy die results:
["DEBUG:",[41440,57949,15946,44821,117168,339337,383339]]
The χ2 statistic for a trial of 1000000 virtual tosses is 982157.0011039999.
Using a two-sided χ2-test with seven degrees of freedom (1.69, 16.013), it is reasonable to conclude that
this is higher than would be expected for a fair die.
High-entropy die results:
["DEBUG:",[142860,143087,142213,142065,143359,143494,142922]]
The χ2 statistic for a trial of 1000000 virtual tosses is 12.298347999999999.
Using a two-sided χ2-test with seven degrees of freedom (1.69, 16.013), it is reasonable to conclude that
this is consistent with the die being fair.
</pre>
=={{header|Julia}}==
<syntaxhighlight lang="julia">
using Random: seed!
seed!(1234) # for reproducibility
dice5() = rand(1:5)
function dice7()
while true
a = dice5()
b = dice5()
c = a + 5(b - 1)
if c <= 21
return mod1(c, 7)
end
end
end
rolls = (dice7() for i in 1:100000)
roll_counts = Dict{Int,Int}()
for roll in rolls
roll_counts[roll] = get(roll_counts, roll, 0) + 1
end
foreach(println, sort(roll_counts))
</syntaxhighlight>
Output:
<pre>
1 => 14530
2 => 13872
3 => 14422
4 => 14425
5 => 14323
6 => 14315
7 => 14113
</pre>
=={{header|Kotlin}}==
<syntaxhighlight lang="scala">// version 1.1.3
import java.util.Random
val r = Random()
fun dice5() = 1 + r.nextInt(5)
fun dice7(): Int {
while (true) {
val t = (dice5() - 1) * 5 + dice5() - 1
if (t >= 21) continue
return 1 + t / 3
}
}
fun checkDist(gen: () -> Int, nRepeats: Int, tolerance: Double = 0.5) {
val occurs = mutableMapOf<Int, Int>()
for (i in 1..nRepeats) {
val d = gen()
if (occurs.containsKey(d))
occurs[d] = occurs[d]!! + 1
else
occurs.put(d, 1)
}
val expected = (nRepeats.toDouble()/ occurs.size).toInt()
val maxError = (expected * tolerance / 100.0).toInt()
println("Repetitions = $nRepeats, Expected = $expected")
println("Tolerance = $tolerance%, Max Error = $maxError\n")
println("Integer Occurrences Error Acceptable")
val f = " %d %5d %5d %s"
var allAcceptable = true
for ((k,v) in occurs.toSortedMap()) {
val error = Math.abs(v - expected)
val acceptable = if (error <= maxError) "Yes" else "No"
if (acceptable == "No") allAcceptable = false
println(f.format(k, v, error, acceptable))
}
println("\nAcceptable overall: ${if (allAcceptable) "Yes" else "No"}")
}
fun main(args: Array<String>) {
checkDist(::dice7, 1_400_000)
}</syntaxhighlight>
Sample output:
<pre>
Repetitions = 1400000, Expected = 200000
Tolerance = 0.5%, Max Error = 1000
Integer Occurrences Error Acceptable
1 199285 715 Yes
2 200247 247 Yes
3 199709 291 Yes
4 199983 17 Yes
5 199990 10 Yes
6 200664 664 Yes
7 200122 122 Yes
Acceptable overall: Yes
</pre>
=={{header|Liberty BASIC}}==
<syntaxhighlight lang="lb">
n=1000000 '1000000 would take several minutes
print "Testing ";n;" times"
if not(check(n, 0.05)) then print "Test failed" else print "Test passed"
end
'function check(n, delta) is defined at
'http://rosettacode.org/wiki/Verify_distribution_uniformity/Naive#Liberty_BASIC
function GENERATOR()
'GENERATOR = int(rnd(0)*10) '0..9
'GENERATOR = 1+int(rnd(0)*5) '1..5: dice5
'dice7()
do
temp =dice5() *5 +dice5() -6
loop until temp <21
GENERATOR =( temp mod 7) +1
end function
function dice5()
dice5=1+int(rnd(0)*5) '1..5: dice5
end function
</syntaxhighlight>
{{Out}}
<pre>
Testing 1000000 times
minVal Expected maxVal
135714 142857 150000
Bucket Counter pass/fail
1 143310
2 143500
3 143040
4 145185
5 140998
6 142610
7 141357
Test passed
</pre>
=={{header|Lua}}==
<syntaxhighlight lang="lua">dice5 = function() return math.random(5) end
function dice7()
Line 899 ⟶ 1,501:
if x > 20 then return dice7() end
return x%7 + 1
end</
=={{header|M2000 Interpreter}}==
We make a stack object (is reference type) and pass it as a closure to dice7 lambda function. For each dice7 we pop the top value of stack, and we add a fresh dice5 (random(1,5)) as last value of stack, so stack used as FIFO. Each time z has the sum of 7 random values.
We check for uniform numbers using +-5% from expected value.
<syntaxhighlight lang="m2000 interpreter">
Module CheckIt {
Def long i, calls, max, min
s=stack:=random(1,5),random(1,5), random(1,5), random(1,5), random(1,5), random(1,5), random(1,5)
z=0: for i=1 to 7 { z+=stackitem(s, i)}
dice7=lambda z, s -> {
=((z-1) mod 7)+1 : stack s {z-=Number : data random(1,5): z+=Stackitem(7)}
}
Dim count(1 to 7)=0& ' long type
calls=700000
p=0.05
IsUniform=lambda max=calls/7*(1+p), min=calls/7*(1-p) (a)->{
if len(a)=0 then =false : exit
=false
m=each(a)
while m
if array(m)<min or array(m)>max then break
end while
=true
}
For i=1 to calls {count(dice7())++}
max=count()#max()
expected=calls div 7
min=count()#min()
for i=1 to 7
document doc$=format$("{0}{1::-7}",i,count(i))+{
}
Next i
doc$=format$("min={0} expected={1} max={2}", min, expected, max)+{
}+format$("Verify Uniform:{0}", if$(IsUniform(count())->"uniform", "skewed"))+{
}
Print
report doc$
clipboard doc$
}
CheckIt
</syntaxhighlight>
{{out}}
<pre style="height:30ex;overflow:scroll">
1 9865
2 10109
3 9868
4 9961
5 9936
6 9922
7 10339
min=9865 expected=10000 max=10339
Verify Uniform:uniform
1 100214
2 100336
3 100049
4 99505
5 99951
6 99729
7 100216
min=99505 expected=100000 max=100336
Verify Uniform:uniform
</pre >
=={{header|Mathematica}}/{{header|Wolfram Language}}==
<syntaxhighlight lang="mathematica">sevenFrom5Dice := (tmp$ = 5*RandomInteger[{1, 5}] + RandomInteger[{1, 5}] - 6;
If [tmp$ < 21, 1 + Mod[tmp$ , 7], sevenFrom5Dice])</syntaxhighlight>
<pre>CheckDistribution[sevenFrom5Dice, 1000000, 5]
->Expected: 142857., Generated :{142206,142590,142650,142693,142730,143475,143656}
->"Flat"</pre>
=={{header|Nim}}==
We use the distribution checker from task [[Simple Random Distribution Checker#Nim|Simple Random Distribution Checker]].
<syntaxhighlight lang="nim">import random, tables
proc dice5(): int = rand(1..5)
proc dice7(): int =
while true:
let val = 5 * dice5() + dice5() - 6
if val < 21:
return val div 3 + 1
proc checkDist(f: proc(): int; repeat: Positive; tolerance: float) =
var counts: CountTable[int]
for _ in 1..repeat:
counts.inc f()
let expected = (repeat / counts.len).toInt # Rounded to nearest.
let allowedDelta = (expected.toFloat * tolerance / 100).toInt
var maxDelta = 0
for val, count in counts.pairs:
let d = abs(count - expected)
if d > maxDelta: maxDelta = d
let status = if maxDelta <= allowedDelta: "passed" else: "failed"
echo "Checking ", repeat, " values with a tolerance of ", tolerance, "%."
echo "Random generator ", status, " the uniformity test."
echo "Max delta encountered = ", maxDelta, " Allowed delta = ", allowedDelta
when isMainModule:
import random
randomize()
checkDist(dice7, 1_000_000, 0.5)</syntaxhighlight>
{{out}}
<pre>Checking 1000000 values with a tolerance of 0.5%.
Random generator passed the uniformity test.
Max delta encountered = 552 Allowed delta = 714</pre>
=={{header|OCaml}}==
<
let dice7 =
Line 918 ⟶ 1,637:
in
aux
;;</
=={{header|PARI/GP}}==
<
dice7()={
Line 927 ⟶ 1,646:
while((t=dice5()*5+dice5()) > 21,);
(t+2)\3
};</
=={{header|
A console application in Free Pascal, created with the Lazarus IDE.
The algorithm suggested in the task description requires on average 50/21 (about 2.38) calls to Dice5 for each call to Dice7. See the link in the VBA solution for a discussion on how to reduce this ratio. It cannot be made less than log_5(7) = 1.209062. The algorithm below is based on Rex Kerr's solution, and requires about 1.2185 calls to Dice5 per call to Dice7. Runtime is about 60% of that for the suggested simple algorithm.
A chi-squared test can be carried out with the help of statistical tables, and is preferred here to an arbitrary "naive" test.
<syntaxhighlight lang="pascal">
unit UConverter;
(*
Defines a converter object to output uniformly distributed random integers 1..7,
given a source of uniformly distributed random integers 1..5.
*)
interface
type
TFace5 = 1..5;
TFace7 = 1..7;
TDice5 = function() : TFace5;
type TConverter = class( TObject)
private
fDigitBuf: array [0..19] of integer; // holds digits in base 7
fBufCount, fBufPtr : integer;
fDice5 : TDice5; // passed-in generator for integers 1..5
fNrDice5 : int64; // diagnostics, counts calls to fDice5
public
constructor Create( aDice5 : TDice5);
procedure Reset();
function Dice7() : TFace7;
property NrDice5 : int64 read fNrDice5;
end;
implementation
constructor TConverter.Create( aDice5 : TDice5);
begin
inherited Create();
fDice5 := aDice5;
self.Reset();
end;
procedure TConverter.Reset();
begin
fBufCount := 0;
fBufPtr := 0;
fNrDice5 := 0;
end;
function TConverter.Dice7() : TFace7;
var
digit_holder, temp : int64;
j : integer;
begin
if fBufPtr = fBufCount then begin // if no more in buffer
fBufCount := 0;
fBufPtr := 0;
repeat // first time through will usually be enough
// Use supplied fDice5 to generate random 23-digit integer in base 5.
digit_holder := 0;
for j := 0 to 22 do begin
digit_holder := 5*digit_holder + fDice5() - 1;
inc( fNrDice5);
end;
// Convert to 20-digit number in base 7. (A simultaneous DivMod
// procedure would be neater, but isn't available for int64.)
for j := 0 to 19 do begin
temp := digit_holder div 7;
fDigitBuf[j] := digit_holder - 7*temp;
digit_holder := temp;
end;
// Maximum possible is 5^23 - 1, which is 10214646460315315132 in base 7.
// If leading digit in base 7 is 0 then low 19 digits are random.
// Else number begins with 100, 101, or 102; and if with
// 100 or 101 then low 17 digits are random. And so on.
if fDigitBuf[19] = 0 then fBufCount := 19
else if fDigitBuf[17] < 2 then fBufCount := 17
else if fDigitBuf[16] = 0 then fBufCount := 16;
// We could go on but that will do.
until fBufCount > 0;
end; // if no more in buffer
result := fDigitBuf[fBufPtr] + 1;
inc( fBufPtr);
end;
end.
program Dice_SevenFromFive;
(*
Demonstrates use of the UConverter unit.
*)
{$mode objfpc}{$H+}
uses
SysUtils, UConverter;
function Dice5() : UConverter.TFace5;
begin
result := Random(5) + 1; // Random(5) returns 0..4
end;
// Percentage points of the chi-squared distribution, 6 degrees of freedom.
// From New Cambridge Statistical Tables, 2nd edn, pp. 40-41.
const
CHI_SQ_6df_95pc = 1.635;
CHI_SQ_6df_05pc = 12.59;
// Main routine
var
nrThrows, j, k : integer;
nrFaces : array [1..7] of integer;
X2, expected, diff : double;
conv : UConverter.TConverter;
begin
conv := UConverter.TConverter.Create( @Dice5);
WriteLn( 'Enter 0 throws to quit');
repeat
WriteLn(''); Write( 'Number of throws (0 to quit): ');
ReadLn( nrThrows);
if nrThrows = 0 then begin
conv.Free();
exit;
end;
conv.Reset(); // clears count of calls to Dice5
for k := 1 to 7 do nrFaces[k] := 0;
for j := 1 to nrThrows do begin
k := conv.Dice7();
inc( nrFaces[k]);
end;
WriteLn('');
WriteLn( SysUtils.Format( 'Number of throws = %10d', [nrThrows]));
WriteLn( SysUtils.Format( 'Calls to Dice5 = %10d', [conv.NrDice5]));
for k := 1 to 7 do
WriteLn( SysUtils.Format( ' Number of %d''s = %10d', [k, nrFaces[k]]));
// Calculation of chi-squared
expected := nrThrows/7.0;
X2 := 0.0;
for k := 1 to 7 do begin
diff := nrFaces[k] - expected;
X2 := X2 + diff*diff/expected;
end;
WriteLn( SysUtils.Format( 'X^2 = %0.3f on 6 degrees of freedom', [X2]));
if X2 < CHI_SQ_6df_95pc then WriteLn( 'Too regular at 5% level')
else if X2 > CHI_SQ_6df_05pc then WriteLn( 'Too irregular at 5% level')
else WriteLn( 'Satisfactory at 5% level')
until false;
end.
</syntaxhighlight>
{{out}}
<pre>
Number of throws = 100000000
Calls to Dice5 = 121846341
Number of 1's = 14282807
Number of 2's = 14282277
Number of 3's = 14288393
Number of 4's = 14285486
Number of 5's = 14289379
Number of 6's = 14291053
Number of 7's = 14280605
X^2 = 6.687 on 6 degrees of freedom
Satisfactory at 5% level
</pre>
=={{header|Perl}}==
Using dice5 twice to generate numbers in the range 0 to 24. If we consider these modulo 8 and re-call if we get zero, we have eliminated 4 cases and created the necessary number in the range from 1 to 7.
<syntaxhighlight lang="perl">sub dice5 { 1+int rand(5) }
sub dice7 {
while(1) {
my $d7 = (5*dice5()+dice5()-6) % 8;
return $d7 if $d7;
}
}
my %count7;
my $n = 1000000;
$count7{dice7()}++ for 1..$n;
printf "%s: %5.2f%%\n", $_, 100*($count7{$_}/$n*7-1) for sort keys %count7;
</syntaxhighlight>
{{out}}
<pre>
1: 0.05%
2: 0.16%
3: -0.43%
4: 0.11%
5: 0.01%
6: -0.15%
7: 0.24%
</pre>
=={{header|Phix}}==
replace rand7() in [[Verify_distribution_uniformity/Naive#Phix]] with:
<!--<syntaxhighlight lang="phix">(phixonline)-->
<span style="color: #008080;">function</span> <span style="color: #000000;">dice5</span><span style="color: #0000FF;">()</span>
<span style="color: #008080;">return</span> <span style="color: #7060A8;">rand</span><span style="color: #0000FF;">(</span><span style="color: #000000;">5</span><span style="color: #0000FF;">)</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">dice7</span><span style="color: #0000FF;">()</span>
<span style="color: #008080;">while</span> <span style="color: #004600;">true</span> <span style="color: #008080;">do</span>
<span style="color: #004080;">integer</span> <span style="color: #000000;">r</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">dice5</span><span style="color: #0000FF;">()*</span><span style="color: #000000;">5</span><span style="color: #0000FF;">+</span><span style="color: #000000;">dice5</span><span style="color: #0000FF;">()-</span><span style="color: #000000;">3</span> <span style="color: #000080;font-style:italic;">-- ( ie 3..27, but )</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">r</span><span style="color: #0000FF;"><</span><span style="color: #000000;">24</span> <span style="color: #008080;">then</span> <span style="color: #008080;">return</span> <span style="color: #7060A8;">floor</span><span style="color: #0000FF;">(</span><span style="color: #000000;">r</span><span style="color: #0000FF;">/</span><span style="color: #000000;">3</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">end</span> <span style="color: #008080;">if</span> <span style="color: #000080;font-style:italic;">-- (only 3..23 useful)</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">while</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<!--</syntaxhighlight>-->
{{out}}
<pre>
1000000 iterations: flat
</pre>
=={{header|PicoLisp}}==
<
(rand 1 5) )
Line 970 ⟶ 1,862:
(use R
(until (> 21 (setq R (+ (* 5 (dice5)) (dice5) -6))))
(inc (% R 7)) ) )</
{{out}}
<pre>: (let R NIL
(do 1000000 (accu 'R (dice7) 1))
Line 979 ⟶ 1,871:
=={{header|PureBasic}}==
{{trans|Lua}}
<
ProcedureReturn Random(4) + 1
EndProcedure
Line 992 ⟶ 1,884:
ProcedureReturn x % 7 + 1
EndProcedure</
=={{header|Python}}==
<
def dice5():
Line 1,002 ⟶ 1,894:
def dice7():
r = dice5() + dice5() * 5 - 6
return (r % 7) + 1 if r < 21 else dice7()</
Distribution check using [[Simple Random Distribution Checker#Python|Simple Random Distribution Checker]]:
<pre>>>> distcheck(dice5, 1000000, 1)
Line 1,009 ⟶ 1,901:
{1: 142853, 2: 142576, 3: 143067, 4: 142149, 5: 143189, 6: 143285, 7: 142881}
</pre>
=={{header|Quackery}}==
<syntaxhighlight lang="quackery"> [ 5 random 1+ ] is dice5 ( --> n )
[ dice5 5 *
dice5 + 6 -
[ table
0 0 0 0 1
1 1 2 2 2
3 3 3 4 4
4 5 5 5 6
6 6 7 7 7 ]
dup 0 = iff
drop again ] is dice7 ( --> n )</syntaxhighlight>
{{out}}
<code>distribution</code> is defined at [[Verify distribution uniformity/Naive#Quackery]].
<pre>/O> ' dice7 1000000 666 distribution
...
[ 143196 142815 143451 142716 142964 142300 142558 ]
Stack empty.</pre>
=={{header|R}}==
5-sided die.
<
Simple but slow 7-sided die, using a while loop.
<
{
score <- numeric()
Line 1,173 ⟶ 1,940:
score
}
system.time(dice7.while(1e6)) # longer than 4 minutes</
More complex, but much faster vectorised version.
<
{
morethan2n <- 3 * n + 10 + (n %% 2) #need more than 2*n samples, because some are discarded
Line 1,192 ⟶ 1,959:
} else score
}
system.time(dice7.vec(1e6)) # ~1 sec</
=={{header|Racket}}==
<syntaxhighlight lang="racket">
#lang racket
(define (dice5) (add1 (random 5)))
(define (dice7)
(define res (+ (* 5 (dice5)) (dice5) -6))
(if (< res 21) (+ 1 (modulo res 7)) (dice7)))
</syntaxhighlight>
Checking the uniformity using math library:
<syntaxhighlight lang="racket">
-> (require math/statistics)
-> (samples->hash (for/list ([i 700000]) (dice7)))
'#hash((7 . 100392)
(6 . 100285)
(5 . 99774)
(4 . 100000)
(3 . 100000)
(2 . 99927)
(1 . 99622))
</syntaxhighlight>
=={{header|Raku}}==
(formerly Perl 6)
{{works with|Rakudo|2018.03}}
<syntaxhighlight lang="raku" line>my $d5 = 1..5;
sub d5() { $d5.roll; } # 1d5
sub d7() {
my $flat = 21;
$flat = 5 * d5() - d5() until $flat < 21;
$flat % 7 + 1;
}
# Testing
my @dist;
my $n = 1_000_000;
my $expect = $n / 7;
loop ($_ = $n; $n; --$n) { @dist[d7()]++; }
say "Expect\t",$expect.fmt("%.3f");
for @dist.kv -> $i, $v {
say "$i\t$v\t" ~ (($v - $expect)/$expect*100).fmt("%+.2f%%") if $v;
}</syntaxhighlight>
{{out}}
<pre>Expect 142857.143
1 143088 +0.16%
2 143598 +0.52%
3 141741 -0.78%
4 142832 -0.02%
5 143040 +0.13%
6 142988 +0.09%
7 142713 -0.10%
</pre>
=={{header|REXX}}==
<syntaxhighlight lang="rexx">/*REXX program simulates a 7─sided die based on a 5─sided throw for a number of trials. */
parse arg trials sample seed . /*obtain optional arguments from the CL*/
if trials=='' | trials="," then trials= 1 /*Not specified? Then use the default.*/
if sample=='' | sample="," then sample= 1000000 /* " " " " " " */
if datatype(seed, 'W') then call random ,,seed /*Integer? Then use it as a RAND seed.*/
L= length(trials) /* [↑] one million samples to be used.*/
do #=1 for trials; die.= 0 /*performs the number of desired trials*/
k= 0
do until k==sample; r= 5 * random(1, 5) + random(1, 5) - 6
if r>20 then iterate
k= k + 1; r= r // 7 + 1; die.r= die.r + 1
end /*until*/
say
expect= sample % 7
say center('trial:' right(#, L) " " sample 'samples, expect' expect, 80, "─")
do j=1 for 7
say ' side' j "had " die.j ' occurrences',
' difference from expected:'right(die.j - expect, length(sample) )
end /*j*/
end /*#*/ /*stick a fork in it, we're all done. */</syntaxhighlight>
{{out|output|text= when using the input of: <tt> 11 </tt>}}
<br>(Shown at five-sixth size.)
<pre style="font-size:84%;height:71ex">
──────────────────trial: 1 1000000 samples, expect 142857──────────────────
side 1 had 142076 occurrences difference from expected: -781
side 2 had 143053 occurrences difference from expected: 196
side 3 had 142342 occurrences difference from expected: -515
side 4 had 142633 occurrences difference from expected: -224
side 5 had 143024 occurrences difference from expected: 167
side 6 had 143827 occurrences difference from expected: 970
side 7 had 143045 occurrences difference from expected: 188
──────────────────trial: 2 1000000 samples, expect 142857──────────────────
side 1 had 143470 occurrences difference from expected: 613
side 2 had 142998 occurrences difference from expected: 141
side 3 had 142654 occurrences difference from expected: -203
side 4 had 142545 occurrences difference from expected: -312
side 5 had 142452 occurrences difference from expected: -405
side 6 had 143144 occurrences difference from expected: 287
side 7 had 142737 occurrences difference from expected: -120
──────────────────trial: 3 1000000 samples, expect 142857──────────────────
side 1 had 142773 occurrences difference from expected: -84
side 2 had 143198 occurrences difference from expected: 341
side 3 had 142296 occurrences difference from expected: -561
side 4 had 142804 occurrences difference from expected: -53
side 5 had 142897 occurrences difference from expected: 40
side 6 had 142382 occurrences difference from expected: -475
side 7 had 143650 occurrences difference from expected: 793
──────────────────trial: 4 1000000 samples, expect 142857──────────────────
side 1 had 143150 occurrences difference from expected: 293
side 2 had 142635 occurrences difference from expected: -222
side 3 had 142763 occurrences difference from expected: -94
side 4 had 142853 occurrences difference from expected: -4
side 5 had 143132 occurrences difference from expected: 275
side 6 had 142403 occurrences difference from expected: -454
side 7 had 143064 occurrences difference from expected: 207
──────────────────trial: 5 1000000 samples, expect 142857──────────────────
side 1 had 143041 occurrences difference from expected: 184
side 2 had 142701 occurrences difference from expected: -156
side 3 had 143416 occurrences difference from expected: 559
side 4 had 142097 occurrences difference from expected: -760
side 5 had 142451 occurrences difference from expected: -406
side 6 had 143332 occurrences difference from expected: 475
side 7 had 142962 occurrences difference from expected: 105
──────────────────trial: 6 1000000 samples, expect 142857──────────────────
side 1 had 142502 occurrences difference from expected: -355
side 2 had 142429 occurrences difference from expected: -428
side 3 had 143146 occurrences difference from expected: 289
side 4 had 142791 occurrences difference from expected: -66
side 5 had 143271 occurrences difference from expected: 414
side 6 had 143415 occurrences difference from expected: 558
side 7 had 142446 occurrences difference from expected: -411
──────────────────trial: 7 1000000 samples, expect 142857──────────────────
side 1 had 142700 occurrences difference from expected: -157
side 2 had 142691 occurrences difference from expected: -166
side 3 had 143067 occurrences difference from expected: 210
side 4 had 141562 occurrences difference from expected: -1295
side 5 had 143316 occurrences difference from expected: 459
side 6 had 143150 occurrences difference from expected: 293
side 7 had 143514 occurrences difference from expected: 657
──────────────────trial: 8 1000000 samples, expect 142857──────────────────
side 1 had 142362 occurrences difference from expected: -495
side 2 had 143298 occurrences difference from expected: 441
side 3 had 142639 occurrences difference from expected: -218
side 4 had 142811 occurrences difference from expected: -46
side 5 had 143275 occurrences difference from expected: 418
side 6 had 142765 occurrences difference from expected: -92
side 7 had 142850 occurrences difference from expected: -7
──────────────────trial: 9 1000000 samples, expect 142857──────────────────
side 1 had 143508 occurrences difference from expected: 651
side 2 had 142650 occurrences difference from expected: -207
side 3 had 142614 occurrences difference from expected: -243
side 4 had 142916 occurrences difference from expected: 59
side 5 had 142944 occurrences difference from expected: 87
side 6 had 143129 occurrences difference from expected: 272
side 7 had 142239 occurrences difference from expected: -618
──────────────────trial: 10 1000000 samples, expect 142857──────────────────
side 1 had 142455 occurrences difference from expected: -402
side 2 had 143112 occurrences difference from expected: 255
side 3 had 143435 occurrences difference from expected: 578
side 4 had 142704 occurrences difference from expected: -153
side 5 had 142376 occurrences difference from expected: -481
side 6 had 142721 occurrences difference from expected: -136
side 7 had 143197 occurrences difference from expected: 340
──────────────────trial: 11 1000000 samples, expect 142857──────────────────
side 1 had 142967 occurrences difference from expected: 110
side 2 had 142204 occurrences difference from expected: -653
side 3 had 142993 occurrences difference from expected: 136
side 4 had 142797 occurrences difference from expected: -60
side 5 had 143081 occurrences difference from expected: 224
side 6 had 142711 occurrences difference from expected: -146
side 7 had 143247 occurrences difference from expected: 390
</pre>
=={{header|Ring}}==
<syntaxhighlight lang="ring">
# Project : Seven-sided dice from five-sided dice
for n = 1 to 20
d = dice7()
see "" + d + " "
next
see nl
func dice7()
x = dice5() * 5 + dice5() - 6
if x > 20
return dice7()
ok
dc = x % 7 + 1
return dc
func dice5()
rnd = random(4) + 1
return rnd
</syntaxhighlight>
Output:
<pre>
7 6 3 5 2 2 7 1 2 7 3 7 4 4 4 2 3 2 6 1
</pre>
=={{header|RPL}}==
<code>UNIF?</code> is defined at [[Verify distribution uniformity/Naive#RPL|Verify distribution uniformity/Naive]]
{{works with|Halcyon Calc|4.2.7}}
≪ ≪ RAND 5 * CEIL ≫ → dice5
≪ '''WHILE'''
dice5 EVAL 5 *
dice5 EVAL 6 - +
DUP 21 ≥
'''REPEAT''' DROP '''END'''
7 MOD 1 +
≫ ≫ '<span style="color:blue">DICE7</span>' STO
≪ <span style="color:blue">DICE7</span> ≫ 100000 .1 <span style="color:blue">UNIF?</span>
{{out}}
<pre>
1: [ 14557 14245 14255 14400 14224 14151 14168 ]
</pre>
Watchdog timer limits the loop to 100,000 items.
=={{header|Ruby}}==
{{trans|Tcl}}
Uses <code>distcheck</code> from [[Simple_Random_Distribution_Checker#Ruby|here]].
<
def d5
Line 1,206 ⟶ 2,205:
def d7
loop do
d55 = 5*d5
return (d55 % 7 + 1) if d55 < 21
end
Line 1,212 ⟶ 2,211:
distcheck(1_000_000) {d5}
distcheck(1_000_000) {d7}</
{{out}}
<pre>1 200227
2 200264
3 199777
4 199387
5 200345
1 143175
2 143031
3 142731
4 142716
5 142931
6 142605
7 142811</pre>
=={{header|Scala}}==
{{Out}}Best seen running in your browser either by [https://scalafiddle.io/sf/3RNtNEC/0 ScalaFiddle (ES aka JavaScript, non JVM)] or [https://scastie.scala-lang.org/Y5qSeW52QiC40l5vJCUMRA Scastie (remote JVM)].
<syntaxhighlight lang="scala">import scala.util.Random
object SevenSidedDice extends App {
private val rnd = new Random
private def seven = {
var v = 21
def five = 1 + rnd.nextInt(5)
while (v > 20) v = five + five * 5 - 6
1 + v % 7
}
println("Random number from 1 to 7: " + seven)
}</syntaxhighlight>
=={{header|Sidef}}==
{{trans|Perl}}
<syntaxhighlight lang="ruby">func dice5 { 1 + 5.rand.int }
func dice7 {
loop {
var d7 = ((5*dice5() + dice5() - 6) % 8);
d7 && return d7;
}
}
var count7 = Hash.new;
var n = 1e6;
n.times { count7{dice7()} := 0 ++ }
count7.keys.sort.each { |k|
printf("%s: %5.2f%%\n", k, 100*(count7{k}/n * 7 - 1));
}</syntaxhighlight>
{{out}}
<pre>1: -0.00%
2: 0.02%
3: 0.23%
4: 0.42%
5: -0.23%
6: -0.54%
7: 0.10%</pre>
=={{header|Tcl}}==
Any old D&D hand will know these as a D5 and a D7...
<
proc D7 {} {
Line 1,229 ⟶ 2,285:
}
}
}</
Checking:
<span class="sy0">%</span> distcheck D5 <span class="nu0">1000000</span>
Line 1,235 ⟶ 2,291:
<span class="sy0">%</span> distcheck D7 <span class="nu0">1000000</span>
1 143121 2 142383 3 143353 4 142811 5 142172 6 143291 7 142869
=={{header|VBA}}==
The original StackOverflow page doesn't exist any longer. Luckily [https://web.archive.org/web/20100730055051/http://stackoverflow.com:80/questions/137783/given-a-function-which-produces-a-random-integer-in-the-range-1-to-5-write-a-fun archive.org] exists.
<syntaxhighlight lang="vb">Private Function Test4DiscreteUniformDistribution(ObservationFrequencies() As Variant, Significance As Single) As Boolean
'Returns true if the observed frequencies pass the Pearson Chi-squared test at the required significance level.
Dim Total As Long, Ei As Long, i As Integer
Dim ChiSquared As Double, DegreesOfFreedom As Integer, p_value As Double
Debug.Print "[1] ""Data set:"" ";
For i = LBound(ObservationFrequencies) To UBound(ObservationFrequencies)
Total = Total + ObservationFrequencies(i)
Debug.Print ObservationFrequencies(i); " ";
Next i
DegreesOfFreedom = UBound(ObservationFrequencies) - LBound(ObservationFrequencies)
'This is exactly the number of different categories minus 1
Ei = Total / (DegreesOfFreedom + 1)
For i = LBound(ObservationFrequencies) To UBound(ObservationFrequencies)
ChiSquared = ChiSquared + (ObservationFrequencies(i) - Ei) ^ 2 / Ei
Next i
p_value = 1 - WorksheetFunction.ChiSq_Dist(ChiSquared, DegreesOfFreedom, True)
Debug.Print
Debug.Print "Chi-squared test for given frequencies"
Debug.Print "X-squared ="; Format(ChiSquared, "0.0000"); ", ";
Debug.Print "df ="; DegreesOfFreedom; ", ";
Debug.Print "p-value = "; Format(p_value, "0.0000")
Test4DiscreteUniformDistribution = p_value > Significance
End Function
Private Function Dice5() As Integer
Dice5 = Int(5 * Rnd + 1)
End Function
Private Function Dice7() As Integer
Dim i As Integer
Do
i = 5 * (Dice5 - 1) + Dice5
Loop While i > 21
Dice7 = i Mod 7 + 1
End Function
Sub TestDice7()
Dim i As Long, roll As Integer
Dim Bins(1 To 7) As Variant
For i = 1 To 1000000
roll = Dice7
Bins(roll) = Bins(roll) + 1
Next i
Debug.Print "[1] ""Uniform? "; Test4DiscreteUniformDistribution(Bins, 0.05); """"
End Sub</syntaxhighlight>
{{out}}<pre>[1] "Data set:" 142418 142898 142940 142573 143030 143139 143002
Chi-squared test for given frequencies
X-squared =2.8870, df = 6 , p-value = 0.8229
[1] "Uniform? True"
</pre>
=={{header|VBScript}}==
<syntaxhighlight lang="vb">Option Explicit
function dice5
dice5 = int(rnd*5) + 1
end function
function
dim j
do
j =
=={{header|Verilog}}==
<syntaxhighlight lang="verilog">
///////////////////////////////////////////////////////////////////////////////
/// seven_sided_dice_tb : (testbench) ///
/// Check the distribution of the output of a seven sided dice circuit ///
///////////////////////////////////////////////////////////////////////////////
module seven_sided_dice_tb;
reg [31:0] freq[0:6];
reg clk;
wire [2:0] dice_face;
reg req;
wire valid_roll;
integer i;
initial begin
clk <= 0;
forever begin
#1;
clk <= ~clk;
end
end
initial begin
req <= 1'b1;
for(i = 0; i < 7; i = i + 1) begin
freq[i] <= 32'b0;
end
repeat(10) @(posedge clk);
repeat(7000000) begin
@(posedge clk);
while(~valid_roll) begin
@(posedge clk);
end
freq[dice_face] <= freq[dice_face] + 32'b1;
end
$display("********************************************");
$display("*** Seven sided dice distribution: ");
$display(" Theoretical distribution is an uniform ");
$display(" distribution with (1/7)-probability ");
$display(" for each possible outcome, ");
$display(" The experimental distribution is: ");
for(i = 0; i < 7; i = i + 1) begin
if(freq[i] < 32'd1_000_000) begin
$display("%d with probability 1/7 - (%d ppm)", i, (32'd1_000_000 - freq[i])/7);
end
else begin
$display("%d with probability 1/7 + (%d ppm)", i, (freq[i] - 32'd1_000_000)/7);
end
end
$finish;
end
seven_sided_dice DUT(
.clk(clk),
.req(req),
.valid_roll(valid_roll),
.dice_face(dice_face)
);
endmodule
///////////////////////////////////////////////////////////////////////////////
/// seven_sided_dice : ///
/// Synthsizeable module that using a 5 sided dice as a black box ///
/// is able to reproduce the outcomes if a 7-sided dice ///
///////////////////////////////////////////////////////////////////////////////
module seven_sided_dice(
input wire clk,
input wire req,
output reg valid_roll,
output reg [2:0] dice_face
);
wire [2:0] face1;
wire [2:0] face2;
reg [4:0] combination;
reg req_p1;
reg req_p2;
reg req_p3;
always @(posedge clk) begin
req_p1 <= req;
req_p2 <= req_p1;
end
always @(posedge clk) begin
if(req_p1) begin
combination <= face1 + face2 + {face2, 2'b00};
end
if(req_p2) begin
case(combination)
5'd0, 5'd1, 5'd2: {valid_roll, dice_face} <= {1'b1, 3'd0};
5'd3, 5'd4, 5'd5: {valid_roll, dice_face} <= {1'b1, 3'd1};
5'd6, 5'd7, 5'd8: {valid_roll, dice_face} <= {1'b1, 3'd2};
5'd9, 5'd10, 5'd11: {valid_roll, dice_face} <= {1'b1, 3'd3};
5'd12, 5'd13, 5'd14: {valid_roll, dice_face} <= {1'b1, 3'd4};
5'd15, 5'd16, 5'd17: {valid_roll, dice_face} <= {1'b1, 3'd5};
5'd18, 5'd19, 5'd20: {valid_roll, dice_face} <= {1'b1, 3'd6};
default: valid_roll <= 1'b0;
endcase
end
end
five_sided_dice dice1(
.clk(clk),
.req(req),
.dice_face(face1)
);
five_sided_dice dice2(
.clk(clk),
.req(req),
.dice_face(face2)
);
endmodule
///////////////////////////////////////////////////////////////////////////////
/// five_sided_dice : ///
/// A model of the five sided dice component ///
///////////////////////////////////////////////////////////////////////////////
module five_sided_dice(
input wire clk,
input wire req,
output reg [2:0] dice_face
);
always @(posedge clk) begin
if(req) begin
dice_face <= $urandom % 5;
end
end
endmodule
</syntaxhighlight>
Compiling with Icarus Verilog
<pre>
> iverilog seven-sided-dice.v -o seven-sided-dice
</pre>
Running the test
<pre>
> vvp seven-sided-dice
********************************************
*** Seven sided dice distribution:
Theoretical distribution is an uniform
distribution with (1/7)-probability
for each possible outcome,
The experimental distribution is:
0 with probability 1/7 + ( 67 ppm)
1 with probability 1/7 - ( 47 ppm)
2 with probability 1/7 + ( 92 ppm)
3 with probability 1/7 - ( 17 ppm)
4 with probability 1/7 - ( 36 ppm)
5 with probability 1/7 + ( 51 ppm)
6 with probability 1/7 - ( 109 ppm)
</pre>
=={{header|Wren}}==
{{trans|Kotlin}}
{{libheader|Wren-sort}}
{{libheader|Wren-fmt}}
<syntaxhighlight lang="wren">import "random" for Random
import "./sort" for Sort
import "./fmt" for Fmt
var r = Random.new()
var dice5 = Fn.new { r.int(1, 6) }
var dice7 = Fn.new {
while (true) {
var t = (dice5.call() - 1) * 5 + dice5.call() - 1
if (t < 21) return 1 + (t/3).floor
}
}
var checkDist = Fn.new { |gen, nRepeats, tolerance|
var occurs = {}
for (i in 1..nRepeats) {
var d = gen.call()
occurs[d] = occurs.containsKey(d) ? occurs[d] + 1 : 1
}
var expected = (nRepeats/occurs.count).floor
var maxError = (expected * tolerance / 100).floor
System.print("Repetitions = %(nRepeats), Expected = %(expected)")
System.print("Tolerance = %(tolerance)\%, Max Error = %(maxError)\n")
System.print("Integer Occurrences Error Acceptable")
var f = " $d $5d $5d $s"
var allAcceptable = true
var cmp = Fn.new { |me1, me2| (me1.key - me2.key).sign }
occurs = occurs.toList
Sort.insertion(occurs, cmp)
for (me in occurs) {
var k = me.key
var v = me.value
var error = (v - expected).abs
var acceptable = (error <= maxError) ? "Yes" : "No"
if (acceptable == "No") allAcceptable = false
Fmt.print(f, k, v, error, acceptable)
}
System.print("\nAcceptable overall: %(allAcceptable ? "Yes" : "No")")
}
checkDist.call(dice7, 1400000, 0.5)</syntaxhighlight>
{{out}}
<pre>
Repetitions = 1400000, Expected = 200000
Tolerance = 0.5%, Max Error = 1000
Integer Occurrences Error Acceptable
1 199744 256 Yes
2 199678 322 Yes
3 200254 254 Yes
4 199903 97 Yes
5 200080 80 Yes
6 200070 70 Yes
7 200271 271 Yes
Acceptable overall: Yes
</pre>
=={{header|zkl}}==
<syntaxhighlight lang="zkl">var die5=(1).random.fp(6); // [1..5]
fcn die7{ while((r:=5*die5() + die5())>=27){} r/3-1 }
fcn rtest(N){ //test spread over [0..9]
dist:=L(0,0,0,0,0,0,0,0,0,0);
do(N){ dist[die7()]+=1 }
sum:=dist.sum();
dist=dist.apply('wrap(n){ "%.2f%%".fmt(n.toFloat()/sum*100) }).println();
}
println("Looking for ",100.0/7,"%");
rtest(0d1_000_000);</syntaxhighlight>
{{out}}
<pre>
Looking for 14.2857%
L("0.00%","14.28%","14.36%","14.22%","14.26%","14.34%","14.33%","14.21%","0.00%","0.00%")
</pre>
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