Anonymous user
Set consolidation: Difference between revisions
m
→{{header|REXX}}: changed/added comments and whitespace, changed indentations.
(Added Elixir) |
m (→{{header|REXX}}: changed/added comments and whitespace, changed indentations.) |
||
Line 1,506:
=={{header|REXX}}==
<lang rexx>/*REXX program demonstrates a method of consolidating some sample sets. */
@.=; @.1 = '{A,B} {C,D}'
@.2 = "{A,B} {B,D}"
Line 1,513:
@.5 = '{snow,ice,slush,frost,fog} {icebergs,icecubes} {rain,fog,sleet}'
do j=1 while @.j\=='' /*traipse through each of sample sets. */
call SETconsolidate @.j /*have the function do the heavy work. */
end /*j*/
exit /*stick a fork in it, we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
isIn: return wordpos(arg(1), arg(2))\==0 /*is (word)
/*──────────────────────────────────────────────────────────────────────────────────────*/
SETconsolidate: procedure;
say ' the old set=' space(old)
do k=1 for # /* [↓] change all commas to a blank. */
!.k=translate(word(old,k), , '},{') /*create a list of words (aka, a set).*/
end /*k*/ /* [↑] ··· and also remove the braces.*/
do until \changed; changed=0 /*consolidate some sets (well, maybe).*/
do set=1 for #-1
do item=1 for words(!.set); x=word(!.set, item)
do other=set+1 to #
if isIn(x, !.other) then do;
!.set=!.set !.other;
iterate set
end
end /*other*/
end /*item */
end /*set */
end /*until ¬changed*/
do set=1 for #; $= /*nullify $ */▼
do items=1 for words(!.set); x=word(!.set, items)▼
if x==',' then iterate; if x=='' then leave▼
do until \isIn(x, !.set)▼
_=wordpos(x, !.set)▼
!.set=subword(!.set,1,_-1) ',' subword(!.set,_+1) /*purify set.*/▼
end /*until ¬isIn ··· */▼
end /*items*/▼
!.set=translate(strip($), ',', " ")▼
end /*set*/▼
do
▲ do items=1 for words(!.set); x=word(!.set, items)
▲ if x==',' then iterate; if x=='' then leave
end /*i*/▼
▲ do until \isIn(x, !.set)
▲ _=wordpos(x, !.set)
▲ end /*items*/
▲ !.set=translate(strip($), ',', " ")
▲ end /*set*/
do i=1 for #; if !.i=='' then iterate /*ignore any set that is a null set. */
say ' the new set=' new; say▼
new=space(new '{'!.i"}") /*prepend and append a set identifier. */
return</lang>▼
▲ end /*i*/
'''output''' when using the default supplied sample sets:▼
▲ say ' the new set=' new; say
▲ return</lang>
▲'''output''' when using the (internal) default supplied sample sets:
<pre>
the old set= {A,B} {C,D}
| |||