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Sequence: nth number with exactly n divisors: Difference between revisions
Sequence: nth number with exactly n divisors (view source)
Revision as of 17:57, 16 May 2020
, 4 years ago→{{header|Haskell}}
Line 411:
calc :: Integer -> [(Integer, Integer)]
calc n = do
where f n = floor (sqrt $ realToFrac n) ^ 2
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