Selectively replace multiple instances of a character within a string: Difference between revisions
Selectively replace multiple instances of a character within a string (view source)
Revision as of 23:25, 5 May 2023
, 1 year agoAdd C
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Line 113:
{{out}}
<pre>AErBcadCbFD</pre>
=={{header|C}}==
<syntaxhighlight lang="c">
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(void) {
const char string[] = "abracadabra";
char *replaced = malloc(sizeof(string));
strcpy(replaced, string);
// Null terminated replacement character arrays
const char *aRep = "ABaCD";
const char *bRep = "E";
const char *rRep = "rF";
for (char *c = replaced; *c; ++c) {
switch (*c) {
case 'a':
if (*aRep)
*c = *aRep++;
break;
case 'b':
if (*bRep)
*c = *bRep++;
break;
case 'r':
if (*rRep)
*c = *rRep++;
break;
}
}
printf("%s\n", replaced);
free(replaced);
return 0;
}
</syntaxhighlight>
{{out}}
<pre>
AErBcadCbFD
</pre>
=={{header|C++}}==
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