Runge-Kutta method: Difference between revisions

Added Easylang
(Added XPL0 example.)
(Added Easylang)
 
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y(10.0) = 675.99994902 Error = 7.5419063100e-8
</pre>
 
=={{header|EasyLang}}==
{{trans|BASIC256}}
<syntaxhighlight>
numfmt 6 0
y = 1
for i = 0 to 100
t = i / 10
if t = floor t
h = t * t + 4
actual = h * h / 16
print "y(" & t & ") = " & y & " Error = " & actual - y
.
k1 = t * sqrt y
k2 = (t + 0.05) * sqrt (y + 0.05 * k1)
k3 = (t + 0.05) * sqrt (y + 0.05 * k2)
k4 = (t + 0.10) * sqrt (y + 0.10 * k3)
y += 0.1 * (k1 + 2 * (k2 + k3) + k4) / 6
.
</syntaxhighlight>
 
=={{header|EDSAC order code}}==
Line 3,725 ⟶ 3,745:
y(9.0) = 451.56245928 Error: 4.07231581e-05
y(10.0) = 675.99994902 Error: 5.09832864e-05</pre>
 
=={{header|V (Vlang)}}==
{{trans|Ring}}
<syntaxhighlight lang="Zig">
import math
 
fn main() {
mut t, mut k1, mut k2, mut k3, mut k4, mut y := 0.0, 0.0, 0.0, 0.0, 0.0, 1.0
for i in 0..101 {
t = i / 10.0
if t == math.floor(t) {
actual := math.pow((math.pow(t, 2) + 4), 2)/16
println("y(${t:.0}) = ${y:.8f} error = ${(actual - y):.8f}")
}
k1 = t * math.sqrt(y)
k2 = (t + 0.05) * math.sqrt(y + 0.05 * k1)
k3 = (t + 0.05) * math.sqrt(y + 0.05 * k2)
k4 = (t + 0.10) * math.sqrt(y + 0.10 * k3)
y += 0.1 * (k1 + 2 * (k2 + k3) + k4) / 6
}
}
</syntaxhighlight>
 
{{out}}
<pre>
y(0) = 1.00000000 error = 0.00000000
y(1) = 1.56249985 error = 0.00000015
y(2) = 3.99999908 error = 0.00000092
y(3) = 10.56249709 error = 0.00000291
y(4) = 24.99999377 error = 0.00000623
y(5) = 52.56248918 error = 0.00001082
y(6) = 99.99998341 error = 0.00001659
y(7) = 175.56247648 error = 0.00002352
y(8) = 288.99996843 error = 0.00003157
y(9) = 451.56245928 error = 0.00004072
y(10) = 675.99994902 error = 0.00005098
</pre>
 
=={{header|Wren}}==
{{trans|Kotlin}}
{{libheader|Wren-fmt}}
<syntaxhighlight lang="ecmascriptwren">import "./fmt" for Fmt
 
var rungeKutta4 = Fn.new { |t0, tz, dt, y, yd|
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