Roots of a function: Difference between revisions

Content added Content deleted
m (add ooRexx)
m (→‎{{header|Julia}}: Updated for Julia 1.3)
Line 1,513: Line 1,513:
<lang Julia>using Roots
<lang Julia>using Roots


println(fzeros(x -> x^3 - 3x^2 + 2x))</lang>
println(find_zero(x -> x^3 - 3x^2 + 2x, (-100, 100)))</lang>


{{out}}
{{out}}