Reduced row echelon form: Difference between revisions

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Hello RosettaCode
Your algorithm/function does NOT work
The "SWAP" is not being done.
Try this matrix to see the problem.
 
//===================================
Linear Algebra with Applications by W. Keith Nicholson, University of Calgary
page 12 - Systems of Linear Equations
 
Solve the following system of equations.
3x + y − 4z = −1
x + 10z = 5
4x + y + 6z = 1
 
Solution. The corresponding augmented matrix is
3 1 −4 −1
1 0 10 5
4 1 6 1
 
Create the first leading one by interchanging rows 1 and 2
1 0 01 5
3 1 −4 −1
4 1 6 1
 
Now subtract 3 times row 1 from row 2, and subtract 4 times row 1 from row 3. The result is
1 0 10 5
0 1 −34 −16
0 1 −34 −19
 
Now subtract row 2 from row 3 to obtain
1 0 10 5
0 1 −34 −16
0 0 0 −3
 
This means that the following reduced system of equations
x + 10z = 5
y − 34z = −16
0 +0 +0 = −3
 
is equivalent to the original system. In other words, the two have the same solutions.
But this last system clearly has no solution (the last equation requires that x, y and z satisfy 0x+0y+0z = −3,
and no such numbers exist).
Hence the original system has no solution.
 
//===========================
 
 
 
{{wikipedia|Rref#Pseudocode}}
Line 2,157 ⟶ 2,110:
0 1 0 1
0 0 1 -2</pre>
 
=={{header|EasyLang}}==
{{trans|Go}}
<syntaxhighlight>
proc rref . m[][] .
nrow = len m[][]
ncol = len m[1][]
lead = 1
for r to nrow
if lead > ncol
0 0 0 −3return
1 0 10 5.
x + 10zi = 5r
while m[i][lead] = 0
4 1 6 i += 1
if i > nrow
i = r
lead += 1
if lead > ncol
return
1 0 10 5 .
4x + y + 6z = 1 .
4 1 6 1.
swap m[i][] m[r][]
m = m[r][lead]
for k to ncol
m[r][k] /= m
.
for i to nrow
if i <> r
m = m[i][lead]
for k to ncol
m[i][k] -= m * m[r][k]
1 0 10 5 .
1 0 01 5 .
.
x + 10zlead += 51
.
.
test[][] = [ [ 1 2 -1 -4 ] [ 2 3 -1 -11 ] [ -2 0 -3 22 ] ]
rref test[][]
print test[][]
</syntaxhighlight>
 
=={{header|Euphoria}}==
Line 5,371 ⟶ 5,367:
{{libheader|Wren-matrix}}
The above module has a method for this built in as it's needed to implement matrix inversion using the Gauss-Jordan method. However, as in the example here, it's not just restricted to square matrices.
<syntaxhighlight lang="ecmascriptwren">import "./matrix" for Matrix
import "./fmt" for Fmt
 
var m = Matrix.new([
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