Read Command-Line Arguments: Difference between revisions

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#REDIRECT [[Command-line arguments]]
{{duplicate}}
{{task}}Read the command line arguments, display the total number, and display each one, including any reference to the program itself. (i.e., if the language includes the name and path of the executable as one of the arguments, include it.)

=={{header|C}}==

<pre>
#include<stdio.h>

int main(int argc, char *argv[])
{
int narg;

printf("There are %d arguments\n", argc);
for(narg=0; narg<argc; ++narg)
printf("Argument #%d is %s.\n", narg, argv[narg]);

return 0;
}
</pre>

=={{header|C++}}==

#include <iostream>
int main( int argc, char *argv[] )
{
std::cout << "There are " << argc << " arguments." << std::endl;
for (int argnum = 0; argnum < argc; ++argnum)
{
std::cout << "Argument #" << argnum << " is " << argv[argnum] << "." << std::endl;
}
return 0;
}

=={{header|Haskell}}==

import System.Environment
main = do
prog <- getProgName
args <- getArgs
putStrLn $ "Program name: " ++ prog
putStrLn $ "There are " ++ show (length args) ++ " arguments:"
forM_ (zip args [1..]) $ \(a,i) ->
putStrLn $ "Argument #" ++ show i ++ " is " ++ a

=={{header|Java}}==
public class CmdLine{
public static void main(String[] args){
System.out.println("Number of args: " + args.length);
for(int i= 0;i < args.length;i++)
System.out.println("Argument #" + (i+1) + ": " + args[i]);
}
}

=={{header|Perl}}==

#!/usr/bin/perl
print "There are $#ARGV arguments.\n";
foreach $argnum ( 0 .. $#ARGV )
{
print "Argument $argnum is $ARGV[$argnum].\n";
}

Latest revision as of 08:24, 2 July 2010